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3 years ago

Which set of side lengths cannot make a triangle?

Mathematics

2 answers:

Ket [755]3 years ago

6 0

Answer:

Option "A" is correct answer to the following question.

Step-by-step explanation:

We know that, in triangle sum of two smaller lines ≥ largest side

So,

3 cm + 3 cm < 6 cm [Not correct to the given situation.]

3 cm + 4 cm > 5 cm [Correct]

3 cm + 5 cm > 7 cm [Correct]

3 cm + 6 cm > 6 cm [Correct]

dlinn [17]3 years ago

4 0

Answer:

A The one that says 3 cm, 3 cm, 6 cm.

Step-by-step explanation:

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Help meee I don't know what to do anymore--

balandron [24]

Answer:

It is increasing by 40 and the first game will 40 the next is 80 the next is 120 and it keeps going on

Step-by-step explanation:

5 0

2 years ago

So, I need to find the Mean Median Mode and Range with this frequency table, and I have no idea how to do that. Can somebody ple

olya-2409 [2.1K]

Mean: average of the numbers. Add them up, divide by how many numbers/entries there are.
-2 + -1 + 0 + 0 + 0 + 0 + 2 + 4 = 3
3 divided by 8 = 0.375
Your mean is 0.375

Median: write the data in numerical order, find the middle number.

-2, -1, 0, 0, 0, 0, 2, 4
In this data set, there are an even number of entries, so we average the middle two numbers. Thankfully, here, the middle two are the same, so your median is 0.

Mode: the number that appears the most often in the data set

Your mode is also 0, because there are more zeroes than any other number in the data set.

Range: the distance on a number line between the highest and lowest number.

The distance between -2 and 4 is 6.4 - (-2) = 6

Please LMK if you have questions

8 0

3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

Step-by-step explanation:

The random variable X is defined as the number of seconds for a randomly selected lap.

The random variable X is normally distributed with mean, μ = 129.71 seconds and standard deviation, σ = 2.28 seconds.

Thus, $X\sim N(129.71,\ 2.28^{2})$ .

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

$P(X$

$=P(Z$

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let x represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of z for the above probability is:

z = -1.88

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42$

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let x₁ and x₂ be the values between which the middle 80% of the distribution lie.

That is,

$P(x_{1}$

The value of z for the above probability is:

z = 1.28

Compute the values of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80$ $z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63$