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Mars2501 [29]
3 years ago
6

(^^tap) SOS having a bit of trouble with this problem​

Mathematics
1 answer:
MrRa [10]3 years ago
5 0

Answer:

x = -5.25 or 21/4

Step-by-step explanation:

When break the bracket out, if there is a minus sign in front of the bracket, when we break it out, the sign inside the bracket would become positive:

67 = 18 - (8x - 7)

67 = 18 - 8x - (-7)

67 = 18 - 8x + 7

67 = 18 + 7 - 8x

67 = 25 - 8x or rewrite for easier look: 25 - 8x = 67

25 - 8x = 67

8x = 25 - 67

8x = -42

Divide both side by 8, we got:

x = -42 / 8

x = -5.25 or 21/4

Hope this helped :3

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Water has a density of 1.0 g/cm3. What is the mass of 10.0 cm3 of water?
fgiga [73]
1.0g/cm3 means that the mass of one cm3 is 1.0g
The easiest method to use is the rule of three, and let x be the mass of 10.0 cm3 of water
1g -- > 1.0 cm3
x --> 10.0 cm3

x= (10*1)/1
x=10.0 g

So the mass of 10.0 cm3 of water is 10.0g

Hope this Helps! :)
8 0
3 years ago
Read 2 more answers
1. D=5.9 ft.
Shtirlitz [24]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

\qquad \sf  \dashrightarrow \:c =  \pi d

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

\qquad \sf  \dashrightarrow \:c =  2\pi r

Now, let's move on to questions ~

<h3>First </h3>

\qquad \sf  \dashrightarrow \:3.14 \times 5.9

\qquad \sf  \dashrightarrow \: \approx18.53 \: ft

<h3 />

・ .━━━━━━━†━━━━━━━━━.・

<h3>Second</h3><h3 /><h3 /><h3 /><h3>\qquad \sf  \dashrightarrow \:3.14 \times 3.2</h3>

\qquad \sf  \dashrightarrow \: \approx10.048 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Third</h3>

\qquad \sf  \dashrightarrow \:3.14 \times 6.1

\qquad \sf  \dashrightarrow \: \approx19.15 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fourth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  3.7

\qquad \sf  \dashrightarrow \: \approx2×11.62  \: m

\qquad \sf  \dashrightarrow \: \approx23.24  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fifth </h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  6.2

\qquad \sf  \dashrightarrow \: \approx2× 19.47 \: units

\qquad \sf  \dashrightarrow \: \approx38.94  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Sixth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  5.1

\qquad \sf  \dashrightarrow \: \approx2×16.01 \: ft

\qquad \sf  \dashrightarrow \: \approx \: 32.02m

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

7 0
2 years ago
What is the sum of all the whole numbers from 1 to 1000?
Katen [24]

Answer:

So there are 500 pairs of numbers that have a sum of 1001. Thus, the sum of numbers from 1 to 1000 is 500*1001 = 500,500.

Step-by-step explanation:

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Which geographic feature was common to the development of civilizations in ancient Egypt, China, India, and Mesopotamia?
storchak [24]
The answer is probably D 
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A group of students is arranging squares into layers to create a project. The first layer has 4 squares. The second layer has 8
stealth61 [152]

Answer:

f(1) = 4; f(n) = 4 + d(n - 1), n > 0.

Step-by-step explanation:

This arithmetic sequence has a common difference of d with first term = 4.

f(1) = 4; f(n) = 4 + d(n - 1), n > 0.

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