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vampirchik [111]

3 years ago

7

A movie theater charges $5 for an adult’s ticket and $2 for a child’s ticket. one saturday, the theater sold 785 tickets for $32

80. how many of each type of ticket were sold?

1 answer:

adelina 88 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

child tickets sold= 215 adult tickets sold= 570

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Henry rolls a standard six-sided die, numbered from 1 to 6. Which word or phrase describes the probability that he will roll a m

DanielleElmas [232]

The answer I would assume is C

7 0

3 years ago

Solve for : x<br> 6x+34+ 8x+14<br> my last one please helpp

mr_godi [17]

Answer:

x = 10

Step-by-step explanation:

8x + 14 = 6x + 34 (vertically opposite angles are equal)

Rearrange

2x = 20

x = 10

3 0

3 years ago

Read 2 more answers

Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

2 years ago

Can someone help me answer this?

lbvjy [14]

Answer:

(30,60)

90mph

Step-by-step explanation:

5 0

3 years ago

Dylan drank 5.2 ounces of water before soccer practice, and 12.9 ounces after practice. Before he drank any water, there were 28

Elan Coil [88]

Answer:

$x=28-5.2-12.9$ , 9.9 ounces of water remaining.

Step-by-step explanation:

<u>Given:</u>

Dylan drank 5.2 ounces of water before soccer practice, and 12.9 ounces after practice.

Before he drank any water, there were 28 ounces of water in the container.

<u>Question asked:</u>

Which expression can be used to find the amount of water remaining?

<u>Solution:</u>

Let $x$ the amount of water remaining.

Total quantity of water in the container = 28 ounces

Before practice, Dylan drank = 5.2 ounces

After practice, Dylan drank = 12.9 ounces

Remaining amount of water = Total quantity of water in the container - Amount of water is drunk before practice - Amount of water is drunk before practice

$x=28-5.2-12.9\\ \\ x=28-18.1\\ \\ x=9.9\ ounces$

Thus, 9.9 ounces of water remaining in the container.

8 0

3 years ago