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AleksandrR [38]
3 years ago
14

Is 1/4 greater than 1/8

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

Yes, 1/4 is bigger than 1/8.

Step-by-step explanation:

So, look at it this way.

1/4, the number 4 has bigger parts than 8. The denominator in 8 has smaller parts. I'm so bad at explaining, but 1/4 is bigger then 1/8.

Here's another way.

Try to get a common denominator. You have to do the same thing to the top when you do something to the bottom.

Common denominators: 2/8.

(Denominator: 8 x 2) (Numerator: 1 x 2) Now, we do not have to change the 1/8. As you can see, now we have 2/8 and 1/8. So, the numerator for 1/4 AKA 2/8 is bigger then 1/8.

I'm so sorry if you do not understand, again and so bad at explaining. It sounds like you are in a younger grade, and I understand. I hope this helps!

lana66690 [7]3 years ago
5 0
Yes, 1/4 is greater than 1/8.

To find out which one is greater, you cross multiply.

8            4
  1       1
  --  x  --
  4       8

The 8 on top of 1/4 shows that is greater than the 4 on top of 1/8.

Hope that helps!
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If 16 = x, then x2=<br> 8<br> 16<br> 4
4vir4ik [10]

Answer:

32?

Step-by-step explanation:

16×2=32

not sure what the numbers after that means but

x8=128

x16=256

x4=64

8 0
3 years ago
70.2 x 10<br> 6.702 x 10?<br> 7.02 x 100<br> 7.02 x 10?
Orlov [11]

Answer:

70.2 x 10=702.

6.702 x 10=67.02

7.02 x 100=70.2

7.02 x 10=70.2

Step-by-step explanation:

I hope this help! :)

3 0
3 years ago
Read 2 more answers
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
4 years ago
NEED HELP ANSWERING ASAP !!
Neporo4naja [7]

Answer:

sorry  can you write it down and take a pic of it

please that is the only way i can answer it

Step-by-step explanation:

8 0
4 years ago
Solve the system by the<br> substitution method.<br> -12x - 2y = -4<br> 6x + 3y = 18
schepotkina [342]

Answer: x = -1 , y = 8✔️

Step-by-step explanation:

-12x - 2y = -4 } Equation 1

6x + 3y = 18 } Equation 2

<em>We can extract the value of x from the equation 2: </em>

6x + 3y = 18 } Equation 2

6x = 18 - 3y

x = (18 - 3y)/6 } Equation 2

<em>Then we can substitute this value of x in equation 1: </em>

-12x - 2y = -4 } Equation 1

-12·(18 - 3y)/6 - 2y = -4

-36 + 6y -2y = -4

4y = -4 + 36

4y = 32

y = 32/4 = 8

<em>Now we can substitute this value of y in equation 2: </em>

x = (18 - 3y)/6 } Equation 2

x = (18 - 3·8)/6 = (18 -24)/6 = -6/6 = -1

Answer: x = -1 , y = 8✔️

<h3>Check </h3>

<em>We can check this result by substituting these values of x and y into the equations: </em>

-12x - 2y = -4 } Equation 1  

-12·(-1) - 2·8 = -4 ► 12 - 16 = -4✔️ checked!

6x + 3y = 18 } Equation 2

6·(-1) + 3·8 = 18 ► -6 + 24 = 18✔️ checked!

<h2><em>Spymore</em></h2>
5 0
3 years ago
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