311,225,823,387,830,850,069
Oof
1: always rearrange the equation to y = mx + c so....
x - y = o
x = y
So the gradient is 1 and it intersects the y axis at (0,0)
The three points could be (1,1), (2,2), (3,3) and so on
2: -x -2y = -10
Multiply everything by -1
x + 2y = 10
2y = 10 - x
y = 5 - x/2
The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on
3: x + y = -2
y = -2 - x
The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on
4: -3y =-x -7
Multiply everything by -1
3y = x + 7
y = x/3 + 7/3
The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o
5: -y = -x + 1
y = x - 1
The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on
Hope this helps! Any questions let me know :)
Answer:
9x
9 • x
9(x)
9*x
I think that's what the question means?
Answer:
y - 5 = -4(x + 3)
Step-by-step explanation:
This question is asking you to use and make an equation using the base of the "point-slope form." This is a common equation used when dealing with coordinates and graphs in math. The point-slope form equation looks like this:
y - y₁ = m(x - x₁).
We are going to need to use this equation base to create our problem from the information given. If you are wondering what those subscripts of 1 mean (the 1 in y₁ and x₁), I will explain. Remember that:
slope (m) = <u>y - y₁</u>
x - x₁
So, our first y value (which is the y-coordinate of 5 in [-3, 5]) can be added into the problem base that I had mentioned above:
y - <u>5</u> = m(x - x₁).
Now, we need to place the first x value (which is the -3 in [-3, 5]) can be added into the base problem once more:
y - 5 = m(x - (<u>-3</u>)).
Because a negative number with a negative symbol in front of it creates a positive, we can change that as well:
y - 5 = m(x + 3).
Fortunately, the question provides a slope ready for use. The question says that the slope is -4, so we can place this into the equation now:
y - 5 = -4(x + 3).
I hope that this helps.
Answer:
15
Step-by-step explanation:
its the same as the other angle on there
