A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter
her second litter had 3 more pups than her first.( first litter +3)=2nd litter
Find the number of pups in her litter
Answer:
She went on the slide 8 times and on the roller coaster 4 times
Step-by-step explanation:
We convert each statements to a mathematical equation.
Firstly, let's represent the number of times she went on the coaster with R and the number of times on the slide with S. We know quite well she went on 12 rides. Hence the summation of both number of times yield 12.
Mathematically, R + S = 12. ........(i)
Now we also know her total wait time was 3hours. Since an hour equals 60 minutes, her total wait time would equal 180 minutes.
To get a mathematical representation for the wait time, we multiply the number of roller coaster rides by 25 and that of the slides by 10.
Mathematically, 25R + 10S = 180 .......(ii)
Here we now have two equations that we can solve simultaneously.
From equation 1 we can say R = 12 - S. We can then substitute this into equation 2 to yield the following:
25(12 - s) + 10s = 180
300 - 25s + 10s = 180
300 - 25s + 10s = 180
300 - 15s = 180
15s = 300 - 180
15s = 120
S = 120/15
S = 8
S = 8 , and R = 12 - S = 12 - 8 = 4
Answer:
π x³ /12 is the volume of the cone if A cone has a height of x and a diameter of x
Step-by-step explanation:
The base diameter and the height of a cone are both equal to x units
Diameter of cone = x units
Radius = Diameter /2
=> Radius of cone = x/2 units
Height of cone =x units
Volume of cone = (1/3) π r²h
r = radius h = height
=> Volume of cone = (1/3)π (x/2)² * x
= (1/3) π (x²/4) * x
= (1/12) π x³
= π x³ /12 cubic units
Answer:
18
Step-by-step explanation:
70^2 = 4900 < 5607 < 6400 = 80^2
so sqrt(5607) is a two-digit number with tenth-digit 7
71^2 = 5041, 72^2 = 5184, 73^2 = 5329, 74^2 = 5476, 75^2 = 5625
so the smallest square bigger than 5607 is 75^2, which is 5625
so the number should ne 5625 - 5607 = 18
