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Reptile [31]
3 years ago
10

Identify any solutions to the system shown here.

Mathematics
2 answers:
OLga [1]3 years ago
8 0
The answer would be B and D.  This can be found by putting the x and y values into the inequality to find whether or not they are true.

xz_007 [3.2K]3 years ago
5 0
Its just a matter of subbing in ur answer choices to see which ones are correct. And for it to be a solution, it has to satisfy both inequalities.

ur answers are : (0.5,2) and (-2,4)
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40 POINTS!!
Kaylis [27]

The answer is C 84. Your welcome

5 0
3 years ago
Read 2 more answers
Given that 5W = 2P + 3R find the value of P when W = 4 and R = −4
Olenka [21]

Answer:

P = 16

Step-by-step explanation:

Given

5W = 2P + 3R ← substitute W = 4 and R = - 4 into the equation

5(4) = 2P + 3(- 4), that is

20 = 2P - 12 ( add 12 to both sides )

32 = 2P ( divide both sides by 2 )

16 = P

5 0
3 years ago
(15) Geometry Help plz
MakcuM [25]
X = measure of angle 1
y = measure of angle 2
z = measure of angle 3
w = measure of angle 4

Focus on the bottom triangle. The three angles add to 180 degrees
(angle 2) + (angle 3) + 116 = 180
y+z+116 = 180
y+z= 180-116
y+z= 64

Since we have the bottom triangle as isosceles, this means that y = z, so
y+z = 64
y+y = 64
2y = 64
y = 64/2
y = 32
making z = 32 as well

Similarly, angle 1 and angle 4 are 32 degrees because the 116 angle is opposite the top left-most angle, and congruent to this angle. In other words, the bottom triangle is a mirror image of the top triangle.

The figure is a rhombus because all four sides are the same length (as shown by the tickmarks)

-----------------------------------------------------------

Answer: 
This figure is a rhombus
All four angles (angle 1 through angle 4) are the same measure. They are each 32 degrees

6 0
3 years ago
5x+7y=31 2x+4y=16 Which of the following systems could be used to solve the given system of equations by the addition method? 10
Pani-rosa [81]
Equation 1: 5x+7y=31
Equation 2: 2x+4y=16

We can either use the 'elimination' method or the 'substitution' method to solve this simultaneous equation.

In some cases one method is easier to use than the other. For this one, it would be easier to use the elimination method

We need to eliminate either the 'x' or the 'y' to begin with. Say we want to eliminate the 'x' terms, then the next step is to make the constant the same

Equation 1: the constant of 'x' is 5
Equation 2: the constant of 'x' is 2

To make the two constants the same, think of common multiple. The lowest common multiple for 5 and 2 is 10

Equation 1:  Multiply all terms by 2 to achieve 10x
Equation 2: Multiply all terms by 5 to achieve 10x

Equation 1: 10x+14y=62
Equation 2: 10x+20y=80

Once the constant of 'x' is the same, then we can start the elimination process. Since our aim is to eliminate, one of the 'x' need to be in negative form. We can either multiply Equation 1 or Equation 2 by (-1)

Equation 1: -10x - 14y = -62
Equation 2: 10x + 20y = 80

Hence the correct answer is: Third option




3 0
3 years ago
I need help can anyone help me with this pls
Cerrena [4.2K]
It might be 2.5 but I could be wrong
3 0
3 years ago
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