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aniked [119]
3 years ago
13

#1. The area of a square tile is 53.4cm^2. find the length of one side of the tile, rounded to the nearest 10th.

Mathematics
2 answers:
andrey2020 [161]3 years ago
5 0

Problem 1

<h3>Answer: 7.3</h3>

Explanation: Apply the square root to the area to get the side length. This only applies to areas that are squares (hence the name).

==================================================

Problem 2

<h3>Answer:  C) 1.3</h3>

Explanation: Use your calculator to find that choices A,B,D plugged into the square root function yield terminating decimal values. "Terminating" means "stop". This implies that they are perfect squares (though not perfect squares in the sense of whole number perfect squares which you may be used to). Choice C is the only value that has a square root that leads to a non-terminating decimal. The digits of this decimal go on forever without any pattern. The value is irrational.

  • sqrt(5.29) = 2.3  terminating decimal
  • sqrt(13.69) = 3.7 terminating decimal
  • sqrt(1.3) = 1.140175425 keeps going forever without any pattern
  • sqrt(0.09) = 0.3 terminating decimal

==================================================

Problem 3

<h3>Answer:  23.6 feet approximately</h3>

Explanation: Apply the square root to 15.5 to get roughly 3.937; this is the approximate side length of one square. Six of these tiles placed together will lead to a total length of roughly 6*3.937 = 23.622 which rounds to 23.6 feet. Like with problem 1, the square root being used like this only works for square areas.

MAVERICK [17]3 years ago
3 0
The answer would be c I believe
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Annabella time for a race was 24.2 seconds. Another runnee's time was 6.43 seconds faster write and evaluate an equation with to
liberstina [14]

Answer:

Step-by-step explanation:

Given Annabella time for a race is 24.2 seconds, if another runnee's time was 6.43 seconds faster, then the time taken for another  runnee's time will be 24.2 - 6.43 = 17.77secs.

Let a variable X be the difference between annabelle's time and the other runners time.

X = annabelle's time  - other runners time.

X = 24.2 - (24.2 - 6.43)

X = 24.2-24.2+6.43

X = 6.43seconds

Hence the expression between annabelle's time and the other runners time is X = 24.2 - (24.2 - 6.43)

<em>The difference between annabelle's time and the other runners time is 6.43seconds</em>

8 0
3 years ago
A student's course grade is based on one midterm that counts as 15% of his final grade, one class project that counts as 15% of
kow [346]

Answer:

Overall final score = 77.75% ; Grade = C.

Step-by-step explanation:

The approach to solve this question is to realize that the marks have to be converted into the respective percentages of the whole course. This means that the marks of all the components have to be normalized according to the grading breakdown.

Project Marks = 97/100. Weightage = 15%. So 97*15/100 = 14.55/15.

This means that the student received 14.55 marks in the project out of 15.

Similarly for other components:

Mid-Term Marks = 83/100. Weightage = 15%. So 83*15/100 = 12.45/15.

Homework Marks = 82/100. Weightage = 35%. So 82*35/100 = 28.7/35.

Finals Marks = 63/100. Weightage = 35%. So 63*35/100 = 22.05/35.

After the conversion process, add up the normalized marks, which are now acting as the percentages earned in all the components.

Aggregate Percentage = 14.55 + 12.45 + 28.7 + 22.05 = 77.75%.

According to the grade scale, the student receives a C because 70 is less than 77.75 and 77.75 is less than 80.

Summarizing, the student receives a C at 77.75%!!!

7 0
3 years ago
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