Answer:
t = 5.25 seconds
Step-by-step explanation:
Given that,
A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation:
It is assumed to find the time when the projectile will hit the ground. When the projectile hit the ground, its height is equal to 0 such that,
It forms a quadratic equation such that,
So, the projectile will hit the ground at t = 5.25 seconds.
Answer:
JL = 52
Step-by-step explanation:
It is given in the question that K is the midpoint of JL.
So, JK = KL ......... (1)
Now, given that, JK =3x - 1 and KL = 2x + 8
Therefore, from equation (1), we can write
3x - 1 = 2x + 8
⇒ x = 9
So, JK = 3x - 1 = 3(9) -1 = 26 and KL = 2x + 8 = 2(9) + 8 = 26
Hence, JL = JK + KL = 26 + 26 = 52. (Answer)
Intersection
Where the graph line matches with which column of graph...... take a line from that place to the axis to identify value on that point of intersection
Hope it helped !!
The 3rd one because of the laws and newton’s ways
Answer:
3x - y = 1
Step-by-step explanation:
This will be the same equation written in a different way'
The original equation is:
y = 3x - 1
0 = 3x - y - 1
3x - y = 1.