Yes
hope this is understandably sure right easy for you
Answer:
I don't know if you wanted it expanded using "Pascal's Triangle" or "Binomial Theorem" but either way is the same. Your expanded equation is:
a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5
I hope this is any help to you, have a nice day.
Step-by-step explanation:
Answer:
E(X) = 6
Var(X) = 3.394
Step-by-step explanation:
Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each
of the (100, 20) ways to catch the 20 fishes will be equally likely.
Thus, we can say that X fulfills a hypergeometric
distribution with parameters as follows;
n = 20, N = 100, k = 30
Formula for expected mean value in hypergeometric distribution is;
E(X) = nk/N
E(X) = (20 × 30)/100
E(X) = 6
Formula for variance is;
Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]
Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]
Var(X) = 6 × 0.5657
Var(X) = 3.394
<h3>The solution by combining like terms is 6.7667</h3>
<em><u>Solution:</u></em>
<em><u>Given expression is:</u></em>
We have to simplify by combining the like terms
From given,
Convert the mixed fraction to improper fraction
Make the denominator same
Thus the solution is 6.7667
