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Evgen [1.6K]
3 years ago
11

Please help !! Confused

Mathematics
2 answers:
Vlad [161]3 years ago
8 0

Answer:

29

Step-by-step explanation:

Alisiya [41]3 years ago
6 0

Answer:

the answer is 29

Step-by-step explanation:

the whole length /AC/ is 40 so since length /AB/ is 11, therefore length /BC/ is 40-11=29

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Can someone please help me I really need help please help me thank you
Vera_Pavlovna [14]

Answer:

D. 2

Step-by-step explanation:

The rate of change is also considered the slope in graph form.

In the first chart every time the t-value goes up twice the c-value goes up four times.

The same can be said for the graph on the bottom.

8 0
3 years ago
PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of
Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0
3 years ago
Read 2 more answers
What is the solution to the quadratic inequality? 8x2≥3+10x (−∞,−14]∪[32,∞) (−∞,−32]∪[14,∞) [−14,32] [−32,14]
Burka [1]

Answer:

umm

Step-by-step explanation:

im in 6th so i dont not know what that means sorry

7 0
4 years ago
West Middle School ordered 121 boxes of markers. If there are 22 teachers, how many boxes does each teacher get? Write your answ
Ilya [14]
Each teacher get 5 1/2 boxes. And do you actually go to West Middle school i went there last year now im a freshman.
8 0
3 years ago
I really dont get this question
Gre4nikov [31]

Answer:

10,000

Step-by-step explanation:

Example:

.01 × 10,000 = 100

4 0
3 years ago
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