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2 years ago

Help me please whats 93 divided by 29 to the power of 3 and multiplied by 283

Mathematics

2 answers:

Lady bird [3.3K]2 years ago

6 0

Answer:

641,894,091

Step-by-step explanation:

guajiro [1.7K]2 years ago

3 0

Answer:

1.07913403584

Step-by-step explanation:

hope it helps you!!

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What is the area of the figure below please explain!

jeyben [28]

I don't know the area of a parallelogram off the top of my head but you can use the area of the rectangle and the area of the triangle and add those. The area of the triangle is 1/2*base*height and use the pythagorean theorem to find the base. 3² + b² = 5²; 9 + b² = 25; b² = 16; b = 4. The area of the triangle is 1/2*4*3 or 6 in. Since there are two of them, the total area of the triangles are 12 in. The area of the rectangle is length*width or (12 - 4) * 3 which is 8 * 3 or 24in. Add these areas together to get 36in total

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2 years ago

The graph of a transformed parabola (green) is

tino4ka555 [31]

The vertex is (-4,5)

7 0

2 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

2 years ago

Chegg: Amoung 400 randomly selected drivers in the 16-18 age bracket, 206 were in a car crash in the last summer. If a driver in

Digiron [165]

The probability of a car crash is 56.75

Approx probability of car crash = 227/400 = 0.5675 i.e. 56.75%

This probability is high enough to be of concern to those in the 16-18 age bracket because the probability is not unlikely.

Probability is the department of mathematics concerning numerical descriptions of the way in all likelihood an occasion is to occur, or how probable it's miles that a proposition is actual. The probability of an occasion is more than a few between zero and 1, in which, kind of talking, 0 indicates impossibility of the occasion and 1 shows actuality.

The probability of an occasion can be calculated through chance system via simply dividing the favorable range of results by using the overall number of possible results.

Learn more about probability here: brainly.com/question/24756209

#SPJ4

8 0

1 year ago

How can doubling a known fact be helpful when finding products mentally

My name is Ann [436]

Answer:

by doing that

Step-by-step explanation:

if x = y so y is z and you can find thatKegunaan Chi-Square:

Uji Chi Square berguna untuk menguji hubungan atau pengaruh dua buah variabel nominal dan mengukur kuatnya hubungan antara variabel yang satu dengan variabel nominal lainnya (C = Coefisien of contingency).

8 0

1 year ago