Help me please whats 93 divided by 29 to the power of 3 and multiplied by 283

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

6 0

Answer:

641,894,091

Step-by-step explanation:

guajiro [1.7K]3 years ago

3 0

Answer:

1.07913403584

Step-by-step explanation:

hope it helps you!!

branliest plssssss

You might be interested in

What is the product of 2p+q and -3q-6p+1

Arlecino [84]

Hey there,

The question is to find the product of the two factors (2p + q)(-3q - 6p + 1).

Now we just multiply across:

-6pq - 12p² + 2p -3q²- 6pq + q

Now we combine like terms:

-12p² - 3q² + 2p + q

So the result would be -12p² - 3q² + 2p + q.

Hope I helped,

Amna

4 0

3 years ago

Please help me if you can. Please also write how you got the answer thank you.

babunello [35]

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

<em />

For question 10, it states $\frac{1}{4}$ . This can be split into $\frac{3}{x}$ and $\frac{3}{x}$ . When x is 12 in the first equation then $\frac{3}{12} = \frac{1}{4}$ and when x is 6 in the second equation $\frac{3}{6} =0.5$ (0.5 is also $\frac{1}{2}$ ). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.