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nasty-shy [4]
3 years ago
9

Stupid question... 4×15​

Mathematics
2 answers:
damaskus [11]3 years ago
6 0

Answer:

60

Step-by-step explanation:

4*15=60

nikklg [1K]3 years ago
4 0

Answer:

60

Step-by-step explanation:

 

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Expand 4x(7x-11)<br>expand 3x(7-5x)<br>Can someone help me with tge questions above?
melamori03 [73]
<span>(    7 x    -    11    )

<span>(   7   -   5x   )</span></span>
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4 years ago
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Which expression is equal to 28 19/100
Leno4ka [110]

Answer:

20 + 8 + 0.1 + 0.9

Step-by-step explanation:


7 0
3 years ago
Due in 7 mins ASAP help plz
s344n2d4d5 [400]
Next is 32,-64
(-4,8,-16,32,-64)
The numbers double each time except it switches from negative to positive
5 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Karo-lina-s [1.5K]

Let us find the co ordinates of each vertex of the triangle .

Vertex A ( in firs second quadrant) = ( -5 ,3)

vertex B in third quadrant = ( -5, -5)

vertex C in fourth quadrant = ( 4, -2)

let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0

AB= 8

BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90

BC = 9.48

AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106

AC= 10.29

Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77

8 0
3 years ago
An angle is drawn in standard position passing through the unit circle at (0.643,0.766). The angle in standard position θ has a
Flura [38]
<h2>Hello!</h2>

The asnwer is: Cos50° ≈ 0.643

<h2>Why?</h2>

A unit circle is a cirgle with a radius equal of 1, knowing that,  also know the following:

The angle is drawn passing trough the unit circle at (0.643,0.766) it means that:

x=0.643\\y=0.766

So,

Cos50° ≈ 0.643

We can prove that by following the next steps:

- If it's a unit circle,here is a right triangle with hypotenuse of 1,

1^{2}=x^{2}+y^{2}

1^{2}=0.643^{2}+0.766^{2}

1^{2}=0.4134 +0.5867

1=1.0001=1

- We can determine the cosine of the angle by the following formula:

cos(\alpha)=\frac{x}{hypotenuse} \\cos(\alpha)^{-1}=cos(\frac{0.643}{1})^{-1} \\\alpha=49.98

Therefore,

Cos(α)=49.98°≈50°

Also, if there is a right triangle, according to the Pythagorean Thorem:

1^{2}=(Cos(\alpha))^{2}+(Sin(\alpha))^{2} \\Cos(50)=\sqrt{1-(Sin(50))^{2}}=0.6427

Hence,

Cos50° ≈ 0.643

Have a nice day!

3 0
3 years ago
Read 2 more answers
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