Answer:
c
Step-by-step explanation:
A relation between two sets is a collection of ordered pairs containing one object from each set. If the object x is from the first set and the object y is from the second set, then the objects are said to be related if the ordered pair (x,y) is in the relation.
A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
The graph represents the relation, but not a function.
This is relation, because it defines the rule for each some such, that the ordered pair (x,y) lies on the graph.
This is not a function, because for all input values of x (excluding x=3) we can find two different output values of y.
Answer:
Total amount Tara earned for babysitting for h hours = 8h
Step-by-step explanation:
Amount earned per hour for babysitting = $8.00
Number of hours of babysitting = h hours
Total amount Tara earned for babysitting for h hours =
Amount earned per hour for babysitting × Number of hours of babysitting
= 8 × h
= 8h
Total amount Tara earned for babysitting for h hours = 8h
Answer:
Step-by-step explanation:
so the steps to doing this are as follows :
Subtract the accepted value from the experimental value.
Take the absolute value of step 1.
Divide that answer by the accepted value.
Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
|18.7-19.3|/19.3 = 0.031088 * 100% = 3.1%
To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
In this problem we have double parentheses. Which one should we solve first? The answer to that is always the inner most ones:
13[ 6² ÷ (5² - 4²) + 9]
5² - 4²
^^^Here you will have to first take the square of both values
25 - 16
9
13[ 6² ÷ (9) + 9]
Now for the exponents
13[ 6² ÷ (9) + 9]
6²
36
13[ 36 ÷ 9 + 9]
Now for the division:
13[ 36 ÷ 9 + 9]
36 ÷ 9
4
13[ 4 + 9]
Now for the addition
13[ 4 + 9]
4 + 9
13
13[13]
Now for multiplication
169
Hope this helped!
~Just a girl in love with Shawn Mendes
