
This equation has only one solution
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P.S. Hello from Russia
Answer:
F=10, S=26
Step-by-step explanation:
We know that the base is 24. Using that information, 10^2+24^2=26^2 which is a pythagorean triple
9514 1404 393
Answer:
x = -6
Step-by-step explanation:
A plot of the points tells you one is above the other on the same vertical line. The equation for a vertical line is ...
x = constant
In order for the line to go through points that have x-coordinates of -6, the constant must be -6. The equation of the line is ...
x = -6
Answer:
f(g(5)) = 16.5
Step-by-step explanation:
To calculate f(g(5)), evaluate g(5) then substitute the value obtained into f(x)
g(5) =
× 5 = 2.5 , then
f(2.5) = 5(2.5) + 4 = 12.5 + 4 = 16.5
<span>et us assume that the origin is the floor right below the 30 ft. fence
To work this one out, we'll start with acceleration and integrate our way up to position.
At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.
To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60
To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4
If the ball clears the fence, it means x = 0, y > 30
x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds
for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft
which is less than 30ft, so it means that the ball will NOT clear the fence.
Just for fun, let's check what the speed should have been :)
x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4
x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s
v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s
So he needed to hit the ball at at least 123.34 ft/s to clear the fence.
You're welcome, Thanks please :)
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