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nexus9112 [7]
3 years ago
5

If Jodi eats 2 chocolates she will consume 72 calories how many calories will she consume if she eats 5 chocolates

Mathematics
2 answers:
musickatia [10]3 years ago
7 0

Answer:

x = 180

Step-by-step explanation:

We can use ratios to solve

2 chocolates        5 chocolates

--------------------- = ------------------

72 calories                x calories

Using cross products

2 *x = 5*72

2x = 360

Divide each side by 2

2x/2 = 360/2

x = 180

77julia77 [94]3 years ago
3 0

Set up a ratio 2/72 = 5/x.

Now use cross-products.

(2)(x) = (5)(72).

2x = 360.

Now divide both sides by 2.

This gives us x = 180.

So, Jodi consumes 180 chocolates when she eats 5 chocolates.

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Completely simplify the rational expression LaTeX: \frac{7x}{3y} + \frac{12x}{9y}
irina [24]

Answer:

\frac{11x}{3y}

Step-by-step explanation:

\frac{7x}{3y} + \frac{12x}{9y}

To add the two fractions, you need a common denominator.  In this case, the lowest common denominator (LCD) is 9y.  That's because 9y is divisible by both 3y and 9y.

The first fraction must be changed so that its denominator is 9y.  Do this by multiplying both numerator and denominator by 3.

\frac{7x}{3y}\cdot\frac{3}{3}+\frac{21x}{9y}=\frac{21x}{9y}+\frac{12x}{9y}\\=\frac{21x+12x}{9y}\\=\frac{33x}{9y}

Finally, this answer can be simplified ("reduced") by dividing both numerator and denominator by 3, their greatest common factor.

3 0
3 years ago
7. Write an equation for the line that is parallel to the given line and that passes through the given point.
Vlad1618 [11]

Answer:

C. y = 1/2x - 14

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  y = 1 /2 x − 8 .

y = 1 /2 x − 14                              PARALLEL

...................................................................................................................................................

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  y = 1 /2 x − 8 .

y = − 2 x − 29                               PERPENDICULAR

8 0
3 years ago
How many yards of the fencing materials do they need for the fence ? explain
labwork [276]

Answer:

152.7 yd

Step-by-step explanation:

I presume that there is a fence around the perimeter and separating the various plots.

AG = BF  = CE = 18 yd

GH = DE = 12 yd

EO² = DE² + DO²

1 5² = 12²  + DO²

225 = 144 + DO²

  81 = DO²

DO = 9

BC = DO = EF  = 9 yd

AC = DH =  EG = 17 yd

AO² = AB² + BO² = 8² + 6² = 64 + 36 =100

AO = √100 = 10 yd

CO² = BC² + BO² = 9² + 6² = 81 + 36 = 127

CO = √127 yd

GO² = FG² + FO² = 8² + 12² =64 + 144 = 208

GO = √208 = 4√13 yd

Fencing needed

= (AC + DH + EG) + (AG + BF + CE) + AO +   CO  + EO + GO

=        (3 × 17)        +         3 × 18)       + 10   + √127 + 15  + 4√13

=           51            +            54          + 25   +  11.27 +          14.42  

=       152.7 yd

8 0
3 years ago
Point D is on segment SF. If SF is 72 cm and DF is 62, what is the measurement of segment SD ?
Anon25 [30]
SD=SF-DF
SD=72-62=10cm
4 0
3 years ago
Read 2 more answers
Two curves are orthogonal if their tangent lines are perpendicular at each point of intersection. are the given families of curv
Akimi4 [234]
Hello,

P(x,y)=x^2+y^2-ax=0\\\\
\dfrac{\partial{P}}{\partial{x}}=2x-a\\\\
\dfrac{\partial{P}}{\partial{y}}=2y\\\\


Q(x,y)=x^2+y^2-by=0\\\\
\dfrac{\partial{Q}}{\partial{x}}=2x\\\\
\dfrac{\partial{Q}}{\partial{y}}=2y-b\\\\

\dfrac{\partial{P}}{\partial{x}}*\dfrac{\partial{Q}}{\partial{x}}+\dfrac{\partial{P}}{\partial{y}}*\dfrac{\partial{Q}}{\partial{y}}=(2x-a)*2x+2y(2y-b)\\
=4x^2+4y^2-2ax-2by\\
=2(2x^2+2y^2-ax-by)\\
=2*P(x,y)+Q(x,y))\\
=2*(0+0)=0\\\\

Answer YES

5 0
3 years ago
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