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Viefleur [7K]
3 years ago
10

... help please :) i really do need the answers

Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0
55 is the answer I just had this question
ELEN [110]3 years ago
4 0

Answer:

.55 since it's literally not anything else

Step-by-step explanation:

.55

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The area of a rectangle is 44m2.The length is 3 2/3. the width is x find the missing length
zimovet [89]
A = lw
44 = 3 2/3 w
w = 44 / (3 2/3)
w = 12
5 0
3 years ago
Describe in your own words what it means to say that integers are closed under addition? (please help I don't get this question)
Naddik [55]

A set  that is closed under an operation or collection of operations is said to satisfy a closure  

property.

For example, the set of even integer is closed under addition, but the set of odd integer is not.  


8 0
3 years ago
Please help me right away with these problems.
viktelen [127]

Q.34

\sum\limits_{k=1}^{\infty}420\left(1.002\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r =1.002 > 1, therefore our infinite geometric series is Diverges

Answer: c. Diverges, sum not exist.

Q.35

\sum\limits_{k=1}^{\infty}-5\left(\dfrac{4}{5}\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r = 4/5 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

S=\dfrac{a_1}{1-r}

We have:

a_1=-5\left(\dfrac{4}{5}\right)^{1-1}=-5\left(\dfrac{4}{5}\right)^0=-5\\\\r=\dfrac{4}{5}

substitute:

S=\dfrac{-5}{1-\frac{4}{5}}=-\dfrac{5}{\frac{1}{5}}=-5\cdot\dfrac{5}{1}=-25

Answer: c. Converges, -25.

4 0
3 years ago
If f(x)= 2^x, then f(log to the base 2 (5))=
AnnyKZ [126]

Let's plug the value:

f(x)=2^x \implies f(\log_2(5))=2^{\log_2(5)}

Recall that exponent and logarithm are inverse operations:

a^{\log_a(b)}=b

So, we have

2^{\log_2(5)}=5

8 0
3 years ago
Write each decimal as a fraction or mixed number in the simplest form.
WARRIOR [948]

Answer:

Need Decimal-

Step-by-step explanation:

8 0
3 years ago
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