7.8+3.5(6.8)-1.5
7.8+23.8-1.5
31.6-1.5
30.1
<h2>
Answer with explanation:</h2>
Let
be the population mean lifetime of circulated $1 bills.
By considering the given information , we have :-

Since the alternative hypotheses is two tailed so the test is a two tailed test.
We assume that the lifetime of circulated $1 bills is normally distributed.
Given : Sample size : n=50 , which is greater than 30 .
It means the sample is large so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


The p-value= 
Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.
Answer:
The correct answer will be "Division".
Step-by-step explanation:
- The procedure represents numerous values requiring something like a conjugate to have been done becomes division, since the denominator conjugate multiplies the numeric values including its quotient to represent the quotient of several complex numbers throughout the standard language.
- It is indeed a method used to separate a set of items across equal proportions.
Answer:
Step-by-step explanation:
60 sec= 1 min
60min=1hour
24hours=1day
7days=1week
52 weeks =1 year
24x7= 168hours in a week
168hours x 52 =8736 hours in a year
8736x60=524160mins
524160mins= 1 year
the heart beats 103680 in a year
the heart will beat 524160/103680=5.05555555556 in a minute