Question

What is the perimeter of ABC with vertices A(-2,9), B(7,-3), and C(-2,-3) and in the coordinate plain?

Answer 1

Answer:

Step-by-step explanation:

A - C = ( -2, 9) - (- 2 -3) 

= ( 0, 12) 

AC = 12 

B - C = (7 - 3) - ( - 2 -3) 

= (9, 0) 

BC = 9 

ABC is a right -angled triangle with AC as the hypotenuse 

AC = sqrt( 9^2 + 12^2) 

= sqrt(81 + 144) 

= srqt(225) 

= 15 

Perimeter = 12 + 9 + 15 

= 36 units 

 So the answer is 36 units

Answer 2

Answer:

36units

Step-by-step explanation: A - C = ( -2, 9) - (- 2 -3) 

= ( 0, 12) 

AC = 12 

B - C = (7 - 3) - ( - 2 -3) 

= (9, 0) 

BC = 9 

ABC is a right -angled triangle with AC as the hypotenuse 

AC = sqrt( 9^2 + 12^2) 

= sqrt(81 + 144) 

= srqt(225) 

= 15 

Perimeter = 12 + 9 + 15 

= 36 units 

 So the answer is 36 units