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nadya68 [22]
3 years ago
7

If in a triangle ABC, a-25, b=16, c=9 then tan(A/2) is?

Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0
We have the following givens:
a=25 
b=16
c=9
We can make use of the Laws of Cosines in solving the angle A such as:
cos A = (b²+c²-a²)/2bc
cos A =((16)²+9²-(25)²)/1*16*9
A=180°

tan (A/2)=tan(180/2)  
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An invoice is dated January 17 with terms of 8/10 , 6/20 , 4/30 , n/40 . find the three final discount dates and the net payment
IRISSAK [1]

Invoice Date = January 17

• First terms:

8/10 and n/40

This means the final discount can be availed "10" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 10 days = January 27

Final Discount Date = Jan 27

The net payment date will be "n/40", which is 40 days from invoice date, thus

Net payment date will be:

Jan 17 - Jan 31 = 14 days

Feb 1 - Feb 26 = 26 days

------------------------------------

40 days

Payment Date = Feb 26

• Second terms:

6/20 and n/40

This means the final discount can be availed "20" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 20 days = Feb 6

Final Discount Date = Feb 6

The net payment date will be "n/40", which is 40 days from invoice date, thus, same as before,

Payment Date = Feb 26

• Third terms:

4/30 and n/40

This means the final discount can be availed "30" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 20 days = Feb 16

Final Discount Date = Feb 16

The net payment date will be "n/40", which is 40 days from invoice date, thus, same as before,

Payment Date = Feb 26

6 0
1 year ago
HELP IS MUCH NEEDED :)
ElenaW [278]
∠ADC = 112°
∠ADC =6x + 7 + 12x - 3

Equate both:
6x + 7 + 12x - 3 = 112

Solve for x :
6x + 7 + 12x - 3 = 112

Combine like terms:
18x + 4= 112

Take away 4 from both sides:
18x = 108

Divide both sides by 18:
x = 6

Find ∠ADB:
6x + 7 = 6(6) + 7 = 43


Answer: ∠ADB = 43°

5 0
3 years ago
Read 2 more answers
Germany, Italy, and Japan formed the Tripartite Pact in part because they:
SVETLANKA909090 [29]

Answer:

hoped to convince the United States to stay out of World War II

Explanation:

just took the quiz :)

7 0
3 years ago
Which set of numbers is arranged in order from least to greatest?
charle [14.2K]
The answer is:  [C]:  -0.7, ⅕, 0.35, ⅔ .
________________________________________
Explanation:
_________________________________________
<span>
Note that in this correct Answer choice "C" given, we have the following arrangement of numbers:
_____________________________________________________
   </span>→ -0.7, ⅕, 0.35, ⅔ ; 
______________________________________
We are asked to find the "Answer choice" (or, perhaps, "Answer choices?") given that show a set of numbers arranged in order from "least to greatest"; that is, starting with a value that is the smallest number in the arrangement, and sequentially progressing, in order from least to greatest, with the largest (greatest) number in the arrangement appearing as the last number in the arrangement.
______________________
Note the EACH of the 4 (four) answer choices given consists of an arrangement with ONLY one negative number, "- 0.7".  Only TWO of the answer choices—Choices "B" and "C"—have an arrangement beginning with the number, "-0.7 ";  So we can "rule out" the "Answer choices: [A] and [D]".
________________________
Let us examine: Answer choice: [B]: <span>-0.7, 0.35, ⅕, ⅔ ; 
</span>_________________________
Note: The fraction, "⅕" = "2/10"; or, write as: 0.2 .
________________________________________
          The fraction, "⅔" = 0.6666667 (that is 0.6666... repeating; so we often               see a "final decimal point" rounded to "7" at some point.
___________________________________________
Through experience, one will be able to automatically look at these 2 (two) fractions and immediately know their "decimal equivalents".
____________________________________________
Otherwise, one can determine the "decimal form" of these values on a calculator by division:
_________________________
→ ⅕ = 1/5 = 1 ÷ 5 = 0.2
_________________________
→ ⅔ = 2/3 = 2 ÷ 3 = 0.6666666666666667
___________________________________
For Answer choice: [B], we have:
______________________________
→   -0.7, 0.35, ⅕, ⅔ ; 
_________________________
→ So, we can "rewrite" the arrangement of "Answer choice [B]" as:
___________________________________________
    →  -0.7, 0.35, 0.2, 0.666666667 ;
________________________________
    → And we can see that "Answer choice: [B]" is INCORRECT; because
"0.2" (that is, "⅕"), is LESS THAN "0.35".  So, "0.35" should not come BEFORE "⅕" in the arrangement that applies correctly to the problem.
_______________________________________
Let us examine: Answer choice: [C]:  -0.7, ⅕, 0.35, 0.666666667 .
____________________________________________
→ Remember from our previous— and aforementioned—examination of "Answer Choice: [B]" ; that:
____________________________ 
→ ⅕ = 0.2 ;   and:
→ ⅔ = 0.666666667
_______________________
So, given:
____________
→ Answer choice: [C]: -0.7, ⅕, 0.35, ⅔ ; 
______________________
→ We can "rewrite" this given "arrangement", substituting our known "decimal values for the fractions:
______________________________
→ Answer choice: [C]: -0.7, 0.2, 0.35, 0.666666667 ;
_________________________________________
→ As mentioned above, this sequence starts with "-0.7", which is the ONLY negative number in the sequence; as such, the next positive number is correct.  Nonetheless, "0.2" (or, "(⅕") is the next number in the sequence, and is greater than "-0.7". The next number is "0.35. "0.35" is greater than "⅕" (or, "0.2"). Then next number is "(⅔)" (or, "0.666666667").
   "(⅔)"; (or, "0.666666667") is greater than 0.35.
____________________________
This set of numbers: "-0.7, ⅕, 0.35, ⅔" ; is arranged in order from least to greatest; which is "Answer choice: [C]: -0.7, ⅕, 0.35, ⅔" ; the correct answer.
________________________________________________________
6 0
3 years ago
If the pattern rule is defined by the equation `t = 6n`, where `t` is the term value and `n` is the term number, what is the one
blagie [28]

Answer:

600

Step-by-step explanation:

Given

equation t = 6n

n is term number

we have to find 100th term.

Thus, term number is 100

substituting 100 in place of n in equation t=6n , we can find the value of 100th term

t = 6*100 = 600

Thus, 100th term is 600.

8 0
3 years ago
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