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3 years ago

10

Help i give many points

1 answer:

Lelechka [254]3 years ago

7 0

Answer:

Step-by-step explanation:

The pic doesnt wrk comment question and ill answer

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ANYONE PLS HELP ASAP!!

Kruka [31]

Answer:

the answer your looking for is 2 2/8 pies

3 0

3 years ago

NEED HELP PLEASE Will Give Brainlist to 1st answer

yuradex [85]

C. Corresponding angles postulate! :)

5 0

3 years ago

The box at the right is a cube with edges that measure 2 feet. The sides of the triangle inside the cube are a diagonal of a fac

zvonat [6]

Answer:

$Area = 2 \sqrt{2}$

Step-by-step explanation:

Given

$Length_1 = 2$

$Length_2 = \sqrt{2^3}$

Required

Determine the area of the triangle

The given lengths represent the height and base length of the triangle.

So, the area is;

$Area = \frac{1}{2} * Length_1 * Length_2$

Substitute values for Length1 and Length2

$Area = \frac{1}{2} * 2 * \sqrt{2^3}$

$Area = \frac{2}{2} * \sqrt{2^3}$

$Area = 1* \sqrt{2^3}$

$Area = \sqrt{2^3}$

Express 2^3 as 2 * 2 * 2

$Area = \sqrt{2*2*2}$

$Area = \sqrt{4*2}$

Split

$Area = \sqrt{4} *\sqrt{2}$

$Area = 2 *\sqrt{2}$

$Area = 2 \sqrt{2}$

6 0

3 years ago

Proof that :<br><img src="https://tex.z-dn.net/?f=%20%7Bsin%7D%5E%7B2%7D%20%5Ctheta%20%2B%20%20%7Bcos%7D%5E%7B2%7D%20%5C%3A%5Cth

Arisa [49]

Answer:

Solution given:

Right angled triangle ABC is drawn where <C= $\theta$

we know that

$\displaystyle Sin\theta=\frac{opposite}{hypotenuse} =\frac{AB}{AC}$

$\displaystyle Cos\theta=\frac{adjacent}{hypotenuse}=\frac{BC}{AC}$

Now

left hand side

$\displaystyle {sin}^{2} \theta + {cos}^{2} \:\theta$

Substituting value

$(\frac{AB}{AC})²+(\frac{BC}{AC})²$

distributing power

$\frac{AB²}{AC²}+\frac{BC²}{AC²}$

Taking L.C.M

$\displaystyle \frac{AB²+BC²}{AC²}$ ....[I]

In ∆ABC By using Pythagoras law we get

$\boxed{\green{\bold{Opposite²+adjacent²=hypotenuse²}}}$

AB²+BC²=AC²

Substituting value of AB²+BC² in equation [I]

we get

$\displaystyle \frac{AC²}{AC²}$

=1

Right hand side

<h3><u>proved</u></h3>

8 0

3 years ago

Read 2 more answers

Will give brainliest to correct answer.

Inga [223]

Use Pythagorean's Theorem to find the length of x. $30^2-16^2=x^2$ so $900-256=x^2$ and $x= \sqrt{644}$ . We can simplify that radicand down into a perfect square times a prime number, and that is $\sqrt{4*161}$ . 4 is a perfect square that can be pulled out as a 2, so the length of x is $2 \sqrt{161}$ , the choice on the top right.

7 0

3 years ago

Read 2 more answers