5 ft 4 in = 64 in
5 ft 10 in = 70 in
F : M
64 : 70
32 : 35
We have:
Thus:
Adding
gives:
Factoring gives:
Thus, we have:
or
.
Note that because
, there will be no solutions
of the form
for positive integer
and solution
. So we find the basic values of
giving
.
For
with positive
,
(this can be seen easily from the unit circle. But
, a contradiction. So we examine the case in which
.
In this case,
. So this is the only solution to this equation.
Substituting this back in, we have
, as desired. So this is a valid solution.
Thus,
.
Answer:
35.45 I just took the test
Step-by-step explanation:
The distance they can see: d = √ ( 3 h / 2 )
d ( Addison ) = √ ( 3 · 256/3 / 2 ) = √ 124 = √ 64 · 2 = 8 √ 2d ( Kaylib ) = √ ( 3 · 48 / 2 ) = √ 72 = √ 36 · 2 = 6 √ 2d ( Addison ) - d ( Kaylib ) = 8 √ 2 - 6 √ 2 = 2 √ 2Answer: b. 2 √ 2 mi.