The smallest unit of measure is the millimeter
Hope this helps ;)
I hope this helps you
(1-cosx)(1+cosx)=1+cosx-cosx-cos²x=1-cos²x=sin²x
sin²x
____
cos²x
tg²x
30 visited nepal only 25 visited Pakistan only. 15 tourists at the intersection of the two circles and 1130 have not visited either
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16
(x^2+10x+16)(x+k)=x^3+9x^2+6x-16
x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16
kx^2+10kx+16k=-x^2-10x-16
k(x^2+10x+16)=-x^2-10x-16
k=(-x^2-10x-16)/(x^2+10x+16)
k=-1
so the width is (x-1)
Answer:
Step-by-step explanation:
1)
O = center of circle (origin)
we know that the angle at the center of the circle ∠ ROS will be
180= 2(31) + ∠x
180-62 = ∠x
118° = ∠x
The supplemental angle to the 118° will be 62°
62° is the interior angle to arc QR , so
arc QR is also 62°
3)
b/c the intercepted arc YZ = 2* 68=136
then 136+125+? = 360
? = 99°
arc ZX = 99°
5)
O= center point
we are given the two arcs 120 and 70 for both of these we know that the
interior angles will be the same. ∠JOX has a central angle of 120 , then
b/c triangle JOX is an isosceles, we know that the two angles J and X of
the triangle JOX will be 1/2 of 60 , or 30 each
also for
also ∠XOY has an interior angle of 70 so the two angle at X and Y will be 1/2 of 110 , or 55°
now add 55+30 to find X for box XYZJ
85° = ∠X
