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kozerog [31]
4 years ago
6

There has been a trend toward less driving in the last few years, especially by young people. From 2001 to 2009 the annual vehic

le miles traveled by people from 16 to 34 years of age decreased from 10,300 to 7900 miles per person (U.S. PIRG and Education Fund website, April 6, 2012). Assume the standard deviation was 2000 miles in 2009. Suppose you would like to conduct a survey to develop a 95% confidence interval estimate of the annual vehicle-miles per person for people 16 to 34 years of age at the current time. A margin of error of 100 miles is desired. How large a sample should be used for the current survey?
Mathematics
1 answer:
rodikova [14]4 years ago
3 0

Answer: 1537.

Step-by-step explanation:

Formula for sample size :-

n=(\dfrac{z_{\alpha/2}\cdot \sigma}{E})^2

Given : \sigma=2000

Margin of error : E= 100

Critical value of 95% confidence : z_{\alpha/2}=1.96

Now, the required sample size will be :-

n=(\dfrac{1.96\cdot 2000}{100})^2\\\\=1536.64\approx1537

Hence, the minimum sample size required = 1537.

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Of the people who fished at Clearwater Park today, 48 had a fishing license, 32and did not. Of the people who fished at Mountain
horrorfan [7]

Answer:

The probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a fisher at Clearwater Park had a fishing license

<em>Y</em> = a fisher at Mountain View Park had a fishing license

The two events are independent.

The information provided is:

n (X) = 48

n (X') = 32

n (Y) = 72

n (Y') = 18

Then,

N (X) = n (X) + n (X')

        = 48 + 32

        = 80

N (Y) = n (Y) + n (Y')

        = 72 + 18

        = 90

Compute the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license as follows:

P(X'\cap Y)=P(X')\times P(Y)

                 =\frac{n(X')}{N(X)}\times \frac{n(Y)}{N(Y)} \\\\=\frac{32}{80}\times\frac{72}{90}\\\\=0.32

Thus, the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.

7 0
3 years ago
Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q2+11q
Sedbober [7]

Answer:

(q+\frac{11}{2})^2-\frac{121}{4}

Step-by-step explanation:

We have been given an expression q^2+11q. We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form a^2+2ab+b^2.

To convert our given expression into perfect square trinomial, we need to add and subtract (\frac{b}{2})^2 from our given expression.

We can see that value of b is 11, so we need to add and subtract (\frac{11}{2})^2 to our expression as:

q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2

Upon comparing our expression with (a+b)^2=a^2+2ab+b^2, we can see that a=q, 2ab=11q and b=\frac{11}{2}.

Upon simplifying our expression, we will get:

(q+\frac{11}{2})^2-\frac{11^2}{2^2}

(q+\frac{11}{2})^2-\frac{121}{4}

Therefore, our perfect square would be (q+\frac{11}{2})^2-\frac{121}{4}.

8 0
3 years ago
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4 10
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No because it doesn’t add up to 180°
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Mrs. Cooper hosts an annual art contest for kids. She has records of the number of entries for the last 9 years. She received 30
Zanzabum

To graph this situation we must take into account the data and the organization of each of them on the X axis and Y axis.

<h3>How to graph this situation?</h3>

To graph this situation we must take into account the data we have:

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Based on these data, we assign the horizontal axis to count years and the vertical axis to count tickets per year. We must continue the pattern of increased attendance over the years.

Learn more about graph in: brainly.com/question/16608196

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