All categories

2 years ago

PLS HURRY GIVING BRAINLIEST

Mathematics

2 answers:

alekssr [168]2 years ago

4 0

Answer:

398 ft²

Step-by-step explanation:

Assuming you have correctly described the total area in terms of non-overlapping triangles and a rectangle, you can put the dimensions into the appropriate area formula and add up the pieces.

Triangle area = 1/2·bh

Rectangle area = bh

___

So, the first triangle has an area of ...

1/2·(20 ft)(20 ft) = 200 ft²

The second triangle has an area of ...

1/2·(6 ft)(6 ft) = 18 ft²

The rectangle has an area of ...

(30 ft)(6 ft) = 180 ft²

And the area total is ...

200 ft² +18 ft² +180 ft² = 398 ft²

hoa [83]2 years ago

3 0

Answer:

Step-by-step explanation:

Given : Bev has to cut her grandma's grass this weekend

Six-sided polygon that includes two isosceles right triangles, one with height and base of 15 feet, the other height and base of 4 feet, and one rectangle measuring 25 feet by 4 feet.

To Find : Area of Polygon

Solution:

Area of triangle = (1/2) bh

= (1/2) * 15 * 15

= 112.5 sq feet

= (1/2) * 4 * 4

= 8 sq feet

Area of rectangle = 25 x 4 = 100 sq feet

Total area =112.5 + 8 + 100

= 220.5 sq feet

Area of Polygon = <u>220.5 sq feet</u>

You might be interested in

Everyone at camp takes turns being on lunch duty. You and your friend are in charge of making sandwiches. you both can make 1 sa

soldi70 [24.7K]

Answer To (b): 10 sandwiches in 20 minutes. But If Your Friend Arrived 10 Minutes Earlier, Then He Can Make 20 Sandwiches In The 20 Minutes That You Are There. If He Started When He Arrived And The Twenty Minutes Started Then, You Can Only Make 5.

4 0

3 years ago

Read 2 more answers

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$