Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
The answer is 2/3 in lowest terms.
The answer would be about
Answer:
Step-by-step explanation:
The value of n should be equal to -27.
The area of the hexagon 24a² -18 is equivalent to 6(4a² -3).
Option A is the correct answer.
<h3>What is a Hexagon ?</h3>
A polygon with 6 sides is called a Hexagon.
The area of a hexagon is equal to area of 6 equilateral triangles.
The area of hexagon is given as
24a² -18
6(4a² -3)
Therefore the area of the hexagon 24a² -18 is equivalent to 6(4a² -3).
Option A is the correct answer.
To know more about Hexagon
brainly.com/question/3295271
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