F(x) = x² + x - 20 = x² + 5x - 4x - 20 = x(x + 5) - 4(x + 5) = (x + 5)(x - 4)
f(x) = 0 ⇔ (x + 5)(x - 4) = 0 ⇔ x + 5 = 0 or x - 4 = 0 ⇒ x = -5 or x = 4
Answer: C. x = -5 and x = 4.
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

It’s the third dot bc X to the tenth power times y divided by three
Answer:
Length
inches
Width
inches
Step-by-step explanation:
Let
= length of rectangle,
= width of rectangle
Given the area and the perimeter of the rectangle, we can write:

So:



Now, we can use substitution to find the value of
:



(Quadratic equation)
∴ 
We can use substitution again to find the value of 



∵ Length usually refers to the longer side of a rectangle, ∴ length
inches and width
inches.
Hope this helps :)
7x - (3x + 7)....not simplified
7x - 3x - 7 =
4x - 7....simplified