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d1i1m1o1n [39]
3 years ago
13

Round .859 to nearest tenth

Mathematics
2 answers:
Marina86 [1]3 years ago
7 0
The answer to this is 0.9
Nikolay [14]3 years ago
6 0
0.9. The reason why is because the 5 brings the 8 to a 9.
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Which can be used to solved the expression (r^-4)^3
Oksana_A [137]

Answer:

The expression is equal to 1 over 12 factors of r

Multiplying the exponents will create an equivalent expression.

Step-by-step explanation:

We are given the following in the question:

(r^-^4)^3

<h3>Properties of exponent: </h3>

(x^m)^n=x^m^n

x^-^a=\frac{1}{x^a}

Thus, we can simplify the given expression as:

(r^-^4)^3

= r^-^1^2

= \frac{1}{r^1^2}

Thus, the correct answer is:

Option 2) The expression is equal to 1 over 12 factors of r

Option 4) Multiplying the exponents will create an equivalent expression.

3 0
3 years ago
What is the slope plllsssss help
Aleks [24]

Answer:

- 2/3

Step-by-step explanation:

(1,4)  (4,2)

Equation To find the slope:

y2 - y1

-------------

x2 - x1

4 - 2       2

-------  =  -----

1 - 4        -3

Hope that helps!

6 0
3 years ago
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The school day consists of six block classes with each being 60 minutes long. Lunch is 25 minutes. Transfer time between classes
jonny [76]

In total the time is 685 min not counting the transfer time and 706 including the transfer time. The probability of lunch fire drill is 25/706. Transfer time in total is 21 min so the probability is 21/207. 2 hours is 120 min. so there is a 120/706 probability that you missed it.

5 0
3 years ago
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Laura has 45 buttons. She gives away b buttons. Write an expression that shows the number of buttons Laura has left.
USPshnik [31]
Giving away indicates subtraction. Therefore, the expression is 45 - b.
6 0
3 years ago
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The probability is 1% that an electrical connector that is kept dry fails during the warranty period of a portable computer. If
rodikova [14]

Answer:

1.4% of connectors fail during the warranty period.

Step-by-step explanation:

We have these following probabilities:

A 90% probability that a connector is kept dry.

A 10% probability that a connectors is wet.

If a connector is dry, an 1% probability of failling.

If a connector is wet, a 5% probability of failling.

What proportion of connectors fail during the warranty period?

This is 1% of 90% and 5% of 10%. So

P = 0.01*0.9 + 0.05*0.1 = 0.014

1.4% of connectors fail during the warranty period.

4 0
3 years ago
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