(12/-3)+(-14*4)
(-4)+(-56)
[-60]
-- i dont understand what you mean by "opposite of" so i assumed you meant negative??
Answer:
128
Step-by-step explanation:
You get this by doing PEMDAS. We start with parenthises and then exponet so we do 4x4 which is 16 now we have 18-16+2 so we go in order and the anwser for the first line is 4 but we have an exponet so 16
now the second line we divide 1 and 4 we get 4 and now we multiply by 1/2 and we get 2. now we have 16/2 that is our anwser and we can put that to a whole number of 128
Answer:
y = (2/5) OR y = (6/5)
Step-by-step explanation:
The first step is isolating the expression within the absolute value bars. The first thing we can do is subtract both sides by 8. If we do that, we get -2|4-5y| = -4. Now, to completely isolate the absolute value, we would have to divide by -2. This yields |4 - 5y| = 2. Finally, we can remove the absolute value bars. However, to do this, we need to first understand what an absolute value bar does to an equation. Lets say that |x| = 2. Absolute value describes the DISTANCE of some quantity from 0 (on the number line). Therefore, x (which is inside the absolute value bars) can be either positive or negative 2 (they are BOTH two units away from 0). Similarly, in this case, (4 - 5y) can either be 2 or -2 (because the absolute value of both is 2). Now we have two possible solutions to solve for:
4 - 5y = 2 OR 4 - 5y = -2
5y = 2 OR 5y = 6
y = (2/5) OR y = (6/5)
If we plug both of these answers back into the equation we can see that they both check out.
<span>L the length W the width
The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W
<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130
by subtitution we replace L by <span>L = 5+ 2W
</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120
w= 20 <span>L = 5+ 2W= 5+ 40=45</span>
