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Citrus2011 [14]
3 years ago
11

.

Mathematics
2 answers:
maxonik [38]3 years ago
8 0
Yes, because there are two pairs of congruent corresponding angles
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

The correct answer is A. Yes, because there are two pairs of congruent corresponding angles.

Step-by-step explanation:

This is because to prove that two triangles are congruent, you need at least two pairs of corresponding angles.

Also, the degrees 30, 65, and 85 is equal to 180 degrees.

Hope this helps!


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Please help me solve this problem ASAP
DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

  • <u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

  • Base = x = 12 inches
  • Perpendicular = z
  • Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

6 0
3 years ago
PLS HALP MEH!!!! A soccer ball is kicked from the ground in an arc defined by the function,h(x) = -2x^2 + 8x. What is the height
AleksAgata [21]
h(3) = -2(3)^{2} + 8(3)
-2(9) + 24
-18 + 24
h(3) = 6
6 0
3 years ago
Read 2 more answers
What is -17/6 plus 5/4?
Ksju [112]

Answer:

exact form : -19/12  Decimal form -1.583 Mixed number form -1  7/12

Step-by-step explanation:

7 0
3 years ago
How can you isolate the variable x on one side of an inequality
Tcecarenko [31]

you combine like terms first.

for example: 2x=2+5

add up the two plus 5 so that will give you seven then you're going to divide 2 by 7 so that you isolate the x and you'll get your answer.

8 0
3 years ago
Solve this system using the Elimination method<br> -4x - 2y =-18 x + 3y = 8
Nutka1998 [239]

Answer:

                                                  Elimination:

-4x - 2y = -18                            -4x - 2y   = -18

x + 3y   = 8        | ×4   ------>    <u>  4x + 12y = 32 </u>  +

                                                          10y = 14

                                                              y = 1,4

x + 3y = 8

x + 3(1,4) = 8

x + 4,2 = 8

x = 3,8

4 0
2 years ago
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