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3 years ago

Given: AB= 4 AD= 6 What point is in the interior of both circles? H A B

Mathematics

2 answers:

fiasKO [112]3 years ago

6 0

For this case we have that, if we look at the figure, we have two circles. The large circle is of radius AD = 6, while the small circle is of radius AB = 4.

We can see that point A is inside the small circle, since the small circle is inside the large one, so A is inside the two circles.

Answer:

Point A

deff fn [24]3 years ago

3 0

That would be point A. Point A is inside the outer bigger circle AND the smaller inner circle

Hope this helped!

~Just a girl in love with Shawn Mendes

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The 59th and 4th team of an Ap are - 61 and 64 respectively. Show that the common differences is - 2.5 and 23rd term is 16.5

Mnenie [13.5K]

Answer:

See answers below

Step-by-step explanation:

T59 = a+58d = -61

T4 = a+3d = 64.

Subtract

58d-3d = -61-64

-55d = -125

d =125/55

d = 25/11

Get a;

From 2

a+3d = 64

a+3(25/11) = 64

a = 64-75/11

a = 704-75/11

a = 629/11

T23 = a+22d

T23 = 629/11+22(25/11)

T23 = 1179/11

3 0

3 years ago

Simplify the following expression: (−3)(−2)( −2)<br> A −12<br> B 12<br> C −18<br> D 18

nydimaria [60]

A -12 Hope this helps

7 0

3 years ago

Read 2 more answers

8. In AABC, LA is a right angle and mzB = 45°. Find BC.

Margaret [11]

Answer:

BC = 11 $\sqrt{2}$

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin45° = $\frac{1}{\sqrt{2} }$ , then

sin 45° = $\frac{opposite}{hypotenuse}$ = $\frac{AC}{BC}$ = $\frac{11}{BC}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

BC = 11 $\sqrt{2}$

7 0

2 years ago

7.2 x 12 x 0.23 = ? Round to the nearest hundredth.

Vlada [557]

$7.2 \times 12\times 0.23 = 19.872\approx \boxed{\bf{19.87}}$

Your final answer is C. 19.87

8 0

3 years ago

Give a brief explanation as to what kind of solution you expect for the linear equation 18x +1/2 equals 6(3x +25). Transform the

Makovka662 [10]

Answer:

there cannot be any solution of the given linear equation.

Step-by-step explanation:

i) the linear equation of 18x + $\frac{1}{2}$ = 6(3x + 25)

ii) transforming the equation to a simpler form we get

18x + $\frac{1}{2}$ = 18x + 150 which implies that $\frac{1}{2}$ = 150 which is not true.

iii) therefore there cannot be any solution of the given linear equation.

6 0

3 years ago