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Dvinal [7]
3 years ago
15

How can you isolate the variable x on one side of an inequality

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

you combine like terms first.

for example: 2x=2+5

add up the two plus 5 so that will give you seven then you're going to divide 2 by 7 so that you isolate the x and you'll get your answer.

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The answer to your question is 5
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What's the sale price if the original price is 83$ and the markdown is 33%
Veronika [31]

Answer:

53.12

Step-by-step explanation:

You can do it 2 ways

1st way

83 multiplied by .33

83 is the amount and .33 is the percent

Now you have the mark downed price, so you subtract that from the original of 83

2nd way

subtract 33 from 100 because the price is 33% off

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3 years ago
How many solutions does y=-7x+8 y=-7x-8 have?
OLga [1]

Answer:

no solutions

Step-by-step explanation:

Given the 2 equations

y = - 7x + 8 → (1)

y = - 7x - 8 → (2)

Substitute y = - 7x - 8 into (1)

- 7x - 8 = - 7x + 8 ( add 8 to both sides )

- 7x = - 7x + 16 (add 7x to both sides )

0 = 16 ← not possible

This indicates the system has no solutions

6 0
3 years ago
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Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they
sp2606 [1]

mechanic #1's rate = x

mechanic #2's rate = y

* Their rate is dollars per hour ($/hr)

mechanic #1 worked for 20 hours (hr × $/hr = $)

20x = money earned by mech#1

and mechanic #2 worked for 5 hours

5y = money earned by mech#2

together they charged a total of $1150. So the amount of money earned by both mechanics.

20x + 5y = 1150

the sum of the two rates was $95 per hour.

x + y = 95

which means

x = 95 - y

plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.

20(95 - y) + 5y = 1150

solve for y

1900 - 20y + 5y = 1150

1900 - 15y = 1150

-15y = 1150 - 1900

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y = -750/-15

y = 50 $/hr

Now use this to solve for x

x + y = 95

x + 50 = 95

x = 95 - 50

x = 45 $/hr

mech#1 charged 45$/hr

mech #2 charged 50$/hr

4 0
3 years ago
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