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3 years ago

What is the value of the expression when n = 3?

Mathematics

1 answer:

inysia [295]3 years ago

3 0

The value of expression when n = 3 is 22

Solution:

Given expression is:

$\frac{6(n^2 + 2)}{n}$

We have to find the value of expression when n = 3

Substitute n = 3 in given expression

$\rightarrow \frac{6(3^2 + 2)}{3}\\\\Simplify\ the\ above\ expression\\\\\rightarrow \frac{6(9+2)}{3}\\\\Solve\ the\ terms\ inside\ the\ bracket\\\\\rightarrow \frac{6(11)}{3}\\\\Divide\ 6\ by\ 3 \\\\\rightarrow 2 \times 11 = 22$

Thus the value of expression when n = 3 is 22

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find an expression for the area of a rectangle of sides 2x+3 and x-1 given that the perimeter is 28cm what is the value of x

Ierofanga [76]

Answer:

4cm

Step-by-step explanation:

Given data

L=(2x+3)

W=(x-1)

P=28cm

A= L*W

A= (2x+3)*(x-1)

open bracket

A= 2x^2-2x+3x-3

collect like terms

A= 2x^2+x-3

P= 2L+2W

P= 2*(2x+3)+2(x-1)

P= 4x+6+2x-2

collect like terms

P= 6x-4

but p= 28

28= 6x-4

28-4= 6x

24= 6x

x= 24/6

x= 4cm

Hence x= 4cm

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3 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

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4 years ago

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