Answer:
I think Frog b wins.
Step-by-step explanation:
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
Notice that x remains x, so the translation is not right or left.
y becomes y + 3. You add 3 to each y-coordinate, so the translation is 3 units up.
Hey there!
The correct choice is positive. You’re adding 7 cents to the total (+7)
Hope this helps you!
God bless ❤️
xXxGolferGirlxXx
Answer:
0.04
Step-by-step explanation:
