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tekilochka [14]
4 years ago
9

Which sentence is written correctly? Kino said that if play practice does not start on time, the director “will be mad.” Kino sa

id that if play practice does not start on time, the director “Will be mad”. Kino said that if play practice does not start on time, the director “will be mad”. Kino said that if play practice does not start on time, the director “Will be mad.”
Mathematics
2 answers:
Dimas [21]4 years ago
5 0
Kino said that if play practice does not start on time, the director “will be mad”.
Anna11 [10]4 years ago
3 0

Answer:

The correct answer is,

Kino said that if play practice does not start on time, the director “will be mad.”

Step-by-step explanation:

For starters, only nouns like <u>SPECIFIC</u> places, brands, and names (first, last, middle, nick, etc.) are capitalized.  

"The comma and period always go inside the closing quotation mark when there is no parenthetical reference. The comma and period always go inside a quotation within another quotation when there is no parenthetical reference. The period goes outside of the quotation mark when using a parenthetical reference."

-leo.stcloudstate.edu/research/puncquotes.html

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Step-by-step explanation:

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Find the difference between8/15 and 2/3 Show all calculations in your final answer.
kherson [118]

Answer:

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}          

Step-by-step explanation:

  • Let the value of a number 'a' be = 8/15
  • Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

         =\frac{8}{15}-\frac{-2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

          =\frac{8}{15}-\left(-\frac{2}{3}\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

          =\frac{8}{15}+\frac{2}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{8+10}{15}

          =\frac{18}{15}

\mathrm{Cancel\:the\:common\:factor:}\:3

           =\frac{6}{5}

Thus,

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}                    
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