Question

Multiply (6z 2 - 4z + 1)(8 - 3z).

Answer 1

(6z² - 4z + 1)(8 - 3z)                          Expand
= 48z² -18z³ - 32z +12z² +8 - 3z       Collect like terms
= -18z³ + 60z² - 35z + 8

(6z² - 4z + 1)(8 - 3z)   = -18z³ + 60z² - 35z + 8

Answer 2

Answer:

Option (d) is correct.

The product of  terms $6z^2-4z+1$ and $8-3z$ is

$-18z^3+60z^2-35z+8$

Step-by-step explanation:

Given two terms $6z^2-4z+1$ and $8-3z$

We have to find the product of the two given terms that is $(6z^2-4z+1)(8-3z)$

Consider $(6z^2-4z+1)(8-3z)$

$(6z^2-4z+1)(8-3z)$ is same as $(8-3z)(6z^2-4z+1)$

To find the product we first multiply each term of first bracket with each term of second one, we get,

$(8-3z)(6z^2-4z+1)=8(6z^2-4z+1)-3z(6z^2-4z+1)$

Multiply , we get,

$8(6z^2-4z+1)-3z(6z^2-4z+1)=48z^2-32z+8-18z^3+12z^2-3z$

Simplify by clubbing together like terms, we get,

$48z^2-32z+8-18z^3+12z^2-3z=-18z^3+60z^2-35z+8$

Thus, the product of  terms $6z^2-4z+1$ and $8-3z$ is $-18z^3+60z^2-35z+8$

Option (d) is correct.