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3 years ago

What is the answer to 7(2e−1)−3=6+6e

1 answer:

8 0

Simplifying
7(2e + -1) + -3 = 6 + 6e

Reorder the terms:
7(-1 + 2e) + -3 = 6 + 6e
(-1 * 7 + 2e * 7) + -3 = 6 + 6e
(-7 + 14e) + -3 = 6 + 6e

Reorder the terms:
-7 + -3 + 14e = 6 + 6e

Combine like terms: -7 + -3 = -10
-10 + 14e = 6 + 6e

Solving
-10 + 14e = 6 + 6e

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-6e' to each side of the equation.
-10 + 14e + -6e = 6 + 6e + -6e

Combine like terms: 14e + -6e = 8e
-10 + 8e = 6 + 6e + -6e

Combine like terms: 6e + -6e = 0
-10 + 8e = 6 + 0
-10 + 8e = 6

Add '10' to each side of the equation.
-10 + 10 + 8e = 6 + 10

Combine like terms: -10 + 10 = 0
0 + 8e = 6 + 10
8e = 6 + 10

Combine like terms: 6 + 10 = 16
8e = 16

Divide each side by '8'.
e = 2

Simplifying
e=2

(sorry, i went into depth)

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How many repeating digits are in the smallest group of repeating digits in the decimal equivalent of the fraction shown?

Anna11 [10]

If x = 745/999, then

999x = 745

1000x - x = 745

This equation tells us that the fractional part of 1000x and x cancel upon subtracting. This means the block of repeating digits must be 3 digits long.

To verify this, suppose we write x = 0.yyy… , where y consists of 3 digits. Then

1000x = y.yyy…

1000x - x = y.yyy… - 0.yyy…

999x = y

x = y/999

which means y = 745.

5 0

3 years ago

A tv originally cost 400$ how much is the final cost of the tv if the sales tax is 8%

weeeeeb [17]

Multiply 400 by 8% and add it to 400:

400 x 0.08 = 32

400 + 32 = 432

Answer: $432

6 0

3 years ago

I need help understanding this ASAP PLZ!!!!

MAXImum [283]

Answer:

$x\geq -2$

Step-by-step explanation:

well the values for x are from -2 to ∞

so we can write it as

$x\geq -2$

5 0

3 years ago

A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su

zaharov [31]

Answer:

After 1st year, the age distribution will be

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

$A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]$

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

$x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

$x_1 = A \cdot x$

$x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = A \cdot x_1$

$x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

4 0

4 years ago

What is the common difference or common ratio of the sequence 3,7,11,15...?

olga55 [171]

Answer: you only add 4 each time

Step-by-step explanation:

8 0

3 years ago