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yKpoI14uk [10]
3 years ago
13

What is the answer to 7(2e−1)−3=6+6e

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0
<span>Simplifying
7(2e + -1) + -3 = 6 + 6e

Reorder the terms:
7(-1 + 2e) + -3 = 6 + 6e
(-1 * 7 + 2e * 7) + -3 = 6 + 6e
(-7 + 14e) + -3 = 6 + 6e

Reorder the terms:
-7 + -3 + 14e = 6 + 6e

Combine like terms: -7 + -3 = -10
-10 + 14e = 6 + 6e

Solving
-10 + 14e = 6 + 6e

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-6e' to each side of the equation.
-10 + 14e + -6e = 6 + 6e + -6e

Combine like terms: 14e + -6e = 8e
-10 + 8e = 6 + 6e + -6e

Combine like terms: 6e + -6e = 0
-10 + 8e = 6 + 0
-10 + 8e = 6

Add '10' to each side of the equation.
-10 + 10 + 8e = 6 + 10

Combine like terms: -10 + 10 = 0
0 + 8e = 6 + 10
8e = 6 + 10

Combine like terms: 6 + 10 = 16
8e = 16

Divide each side by '8'.
e = 2

Simplifying
<span>e=2
</span></span>
(sorry, i went into depth)
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How many ways can a dance instructor send 4 of her 11 students to a summer dance program?
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Answer:

d) 330

Step-by-step explanation:

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is  C(11 , 4)

That is 11_{C_{4} } ways

by using formula n_{C_{r} } = \frac{n!}{(n-r)!r!}

now simplification

11_{C_{4} } = \frac{11!}{(11-4)!4!}

      = \frac{11X10X9X8X7!}{(7!)4X3X2X1}

after cancelling 7! and on simplification

   = \frac{11X10X9X8}{4X3X2X1}

after cancellation we get 330 ways

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is 330

   

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3 years ago
your total savings varies inversely with the amount spent on Bill's. if your savings is $300 when your cost of Bill's are $65. W
tatyana61 [14]
Let S and B be savings and bills respectively. Then,
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