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faust18 [17]
3 years ago
15

Please help! Twenty points.

Mathematics
2 answers:
aleksandrvk [35]3 years ago
5 0
C but i need 20 characters so......
rjkz [21]3 years ago
3 0
Spefify your help please
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PLEASE HELP I ASKED THIS QUESTION YESTERDAY AND NOBODY ANSWERED.
ehidna [41]
Graph A is correct! :)
4 0
2 years ago
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Above are two different models of the same diamond-shaped platform. If the length of side a is 3 cm, what is the length of side
Nezavi [6.7K]
The length of side b is also probably 3cm, because thinking of a diamond shape, all of the sides are equal and It give you no other measurments
3 0
3 years ago
Read 2 more answers
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never [62]
$54.80 is the correct answer
3 0
3 years ago
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Use any order, any grouping to write an equivalent expression: 3(2x) + 4y(5) + (4 x 2 x z)
enyata [817]

Answer:

We conclude that the equivalent expression is:

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z

Step-by-step explanation:

Given the expression

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)

Remove parentheses: (a) = a

=3\times \:2x+4\times \:5y+4\times \:2z

Multiply the numbers: 3 ×  2 = 6

=6x+4\times \:5y+4\times \:2z

Multiply the numbers: 4 × 5 = 20

=6x+20y+4\times \:2z

Multiply the numbers: 4 × 2 = 8

=6x+20y+8z

Thus, we conclude that the equivalent expression is:

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z

8 0
3 years ago
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