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Elanso [62]
3 years ago
13

When does the graph of a quadratic function open up?open down?

Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

1. >

2. <

Step-by-step explanation:

When a > 0, the graph opens upwards, or positively, because the way the line curves is determined by a.

When a < 0, the graph opens downwards, or negatively, for the same reason.

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
From the 1,2,3,4,5 which values make the inequality n+1 &gt; 4 true?
ELEN [110]

Answer:

yes it is

Step-by-step explanation:

hope I helped;)

4 0
3 years ago
Read 2 more answers
I don't know how to explain it but please help!
Wittaler [7]

Answer:

required answer. is 1/x³

7 0
2 years ago
1/2 of blank equals 62
Damm [24]

The answer you are looking for is 124.

You can find this answer by simply multiplying 62 by 2.

I hope this helps!

5 0
3 years ago
Read 2 more answers
What do you think the hypervolume of a hypercube is? Why?
gavmur [86]

Answer:

a^4 Where (a) is the side length of the hypercube

Step-by-step explanation:

A dimension can be simply defined as a direction in which matter can move it.

We live in a 3-dimensional world, matter can move in three basic directions. The formula for finding the volume of a cube is the following: (a^3). In the second dimension, a flat world, the area for the volume of a square is as follows: (a^2). However, a hypercube is a paradox, as it exists in 4-dimensions, thus it cannot exist in our world. However, scientists propose "String theory" which requires that matter can move in more directs than the (3) we know of in our world. In essence, there can be more than 3 dimensions. A hypercube is the 4-dimensional version of a cube. If it follows the area pattern that a square-object follows in all preceding dimensions then the area of a hypercube is (a^4).

Bear in mind that the area patter for a square-object is generally the following:

a^n

Where (a) is the side length of the square-object

(n) is the dimension the object is in.

Please keep in mind, this answer was written in the June of 2021, as science keeps progressing and new discoveries are made, this theory can be disproven. Therefore, this answer might be considered correct now, but it can be proven incorrect in the future.

6 0
2 years ago
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