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Slav-nsk [51]
3 years ago
8

HELP PLZ PICK ONE OF THE ONES SHOWN:

Mathematics
1 answer:
defon3 years ago
6 0

I am doing with Question Number 2

Let the two numbers be 'x' and 'y'.

According to the question, the product of two numbers is 14.

x \times y=14

So, xy=14 (Equation 1)

Now, one of the numbers is 3 ½ times the other.

So, x = 3\frac{1}{2}\times y

x=\frac{7}{2}y (Equation 2)

Substituting the value of 'x' from equation 2 in equation 1, we get

\frac{7}{2}y \times y = 14

\frac{7}{2}y^{2} = 14

y^{2} = 4

So, y= 2 and -2

So, x=\frac{14}{2} and x=\frac{14}{-2}

x=7 and -7

Numbers are 2,7 and -2,-7.

Sum of numbers 2 and 7 = 9

Sum of numbers -2 and -7 = -9.


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lbvjy [14]

That does not make any since...

3 0
3 years ago
Find one solution for the equation. Assume that all angles involved are acute angles. tangent (3 Upper B minus 32 degrees )equal
raketka [301]

Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

B = 14° .

5 0
3 years ago
A jet moving at constant speed traveled 6,600 km in 3 hours. What was the speed of the jet?
DanielleElmas [232]

Answer:

The speed of the jet is 2,200\frac{km}{h}

Step-by-step explanation:

The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.

1. Write the general equation for the speed:

Speed=\frac{Distance}{Time}

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:

Speed=\frac{6,600km}{3hours}

Speed=2,200\frac{km}{h}

Therefore the speed of the jet is 2,200\frac{km}{h}

3 0
3 years ago
Read 2 more answers
Figure ABCD is a parallelogram.
STatiana [176]
The answer is 14 units
7 0
3 years ago
What is the equation of a line that passes through the points (-3, 4) and (2,8)?
ziro4ka [17]

Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,4) and (2,8) in the above formula, we get;

m=\frac{8-4}{2+3}

m=\frac{4}{5}

Thus, the slope of the line is m=\frac{4}{5}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-3,4) and m=\frac{4}{5} in the above formula, we have;

y-4=\frac{4}{5}(x+3)

y-4=\frac{4}{5}x+\frac{12}{5}

     y=\frac{4}{5}x+\frac{12}{5}+4

     y=\frac{4}{5}x+\frac{32}{5}

Thus, the equation of the line is y=\frac{4}{5}x+\frac{32}{5}

6 0
3 years ago
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