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jeka94
3 years ago
15

Solve the following multiplication and division problems.

Mathematics
1 answer:
algol133 years ago
5 0

Answer:

a. 22.5 km

b. 267.52 m

c. 95 m

d. (4.2)(10^{-5}) km

Step-by-step explanation:

a. You can convert from hectometers to kilometers, and then you can make the multiplication:

\frac{5hm}{10}=0.5km

(3km)(0.5km)(15)=22.5km

b. You can convert from centimeters to meters, and then you can make the multiplication:

\frac{44cm}{100}=0.44m\\(19m)(0.44m)(32)=267.52m

c. You only need to divide 1,140 meters by 12:

\frac{1,140m}{12})=95m

d. You can convert from hectometers to kilometers, from decameters to kilometers and from meters to kilometers, and divide this by 15:

\frac{6hm}{10}=0.6km

\frac{7dam}{100}=0.07km

\frac{5m}{1000}=0.005km

\frac{(3km)(0.6km)(0.07km)(0.005km)}{15}=(4.2)(10^{-5}) km

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3 years ago
2d +9= 19<br> The solution is d =
Novosadov [1.4K]

{\huge{\boxed{\mathbb{QUESTION}}}

2d +9= 19

The solution is d =

{\huge{\boxed{\mathbb{ANSWER\:WITH\:EXPLANATION}}}

Hello there, first we can place our equation, which you have stated

2d+9=19, this algebra, in algebra we want to find the exact value of the variable, or have the variable on one side of the equation.

First we can subtract 9 with both sides of the equation giving us the result of 2d=10, this can also be represented as 2\cdot d=10, now just divide both sides of the equation by 2, our answer is d=5.

_____________________

{\huge{\boxed{\mathbb{ANSWER}}}

  • {\boxed{d=5}}

_____________________

<h3><em>Have a good day :) !</em></h3>
6 0
3 years ago
There are 16 pieces of fruit in a basket, including 2 nectarines. What is the probability that a randomly selected piece of frui
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Answer:

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Step-by-step explanation:

We have 2 nectarines in a total of 16 pieces of fruit in a basket, so the probability of random selected piece of fruit being a nectarine is the number of nectarines over the total number of pieces of fruit:

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To find the fraction in the simplest form, we divide the numerator and denominator by 2:

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