3 years ago

Number 20! Please help thank you!!!

Mathematics

1 answer:

Ghella [55]3 years ago

3 0

Answer:

$x=6$

Step-by-step explanation:

we know that

If SQ is an angle bisector

then

$m\angle TSQ=m\angle QSR$

we have

$m\angle TSQ=(5x+3)^o$

$m\angle OSR=(10x-27)^o$

substitute the given values

$(5x+3)^o=(10x-27)^o$

solve for x

Group terms

$10x-5x=3+27$

Combine like terms

$5x=30$

Divide by 5 both sides

$x=6$

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