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Radda [10]
3 years ago
9

(#5) A carpenter has two different-sized circular saws. The smaller saw has the radius shown. I couldn't show it, so it is 1.25

inches. The larger saw has a diameter that is 1.5 inches greater than the diameter of the smaller one. How much greater is the circumference of the larger saw than the smaller saw? Use 3.14 for π. Attach a picture of your work. *
Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Answer:

4.71 in. difference

Step-by-step explanation:

so, the radius of the smaller saw is 1.25 and the diameter is double the radius. so it is 2.5 in diameter. the larger saw is 1.5 in greater which is 4 in.

to find circumference, you have to use the solution C = πd or circumference = pi x diameter.

3.14 x 2.5 = 7.85

4 x 3.14 = 12.56

subtract 7.85 from 12.56 to get your answer! i hope this helps!

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Step-by-step explanation:

By Pythagoras theorem,

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5 0
3 years ago
Solve y over negative 2 5 = 13.
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Y/-2 + 5 = 13
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2 years ago
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What type of transformation transforms (a, b) to ​(−a, b)​?
Vikentia [17]
Hello : 
<span>a reflection over the y-axis</span>
7 0
3 years ago
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A cylinder has a radius of 8 meters and a height of 4 meters. .
Novay_Z [31]
<h2><u>Solution</u> :-</h2>

Given : Radius of cylinder = 8 m

Height = 4 m

Volume of cylinder = πr²h cu. units

= 22/7 × 8 × 8 × 4 m³

= 804.57 m³ (approx.)

Curved surface area = 2πrh sq. units

= 2 × 22/7 × 8 × 4 m²

= 201.14 m² (approx.)

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4 0
3 years ago
Nine scores have an average of 8. Scores x and x+1 are added, and these increase the average to 9. Find x
Degger [83]

Answer:

x must be 13

Step-by-step explanation:

Represent the nine scores by a, b, c, d, e, f, g, h, i.

Write the following equation to indicate that the average of these nine scores is 8:

a+b+c+d+e+f+g+h+i

----------------------------- = 8, or <em>a+b+c+d+e+f+g+h+i = 72</em> if we multiply both

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Next, we add scores x and x+ 1 to

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and divide the result by 11, as there are now 11 scores instead of just 9:

a+b+c+d+e+f+g+h+i  +  x + x + 1

----------------------------------------------

                        11

Earlier, we saw that a+b+c+d+e+f+g+h+i = 72.  We can now replace

a+b+c+d+e+f+g+h+i in the above fraction by 72:

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         11

Multiplying both sides of this equation by 11 results in:

73 + 2x = 99, or  2x = 26.

Then x must be 13, and x + 1 must be 14.

3 0
3 years ago
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