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Damm [24]
3 years ago
14

PLEASE HELP:) :( What is the area of this Polygon? Enter your answer in the box

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0
7 x 5 = 35

1/2(7) x 2
3.5 x 2
7

35 + 7 = 42 Units squared
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Please answer this question fast
Sphinxa [80]

Answer:

I think it is 6(5/6)

6 0
3 years ago
What is 800-5x divided by 6.5
MA_775_DIABLO [31]

Answer:10 over 13 x

Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2

to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13

factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)

for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x

solution: 800-10 over 13x so your answer would still be

8 0
3 years ago
Jake has decided to invest in three business ventures. The total cost of investing in all three ventures is $15,000. The combine
Arte-miy333 [17]
X = first venture, y = second venture, z = third venture

x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....

x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000

x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000

2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000

x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000

first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
7 0
3 years ago
Read 2 more answers
Please help 20-23 it is 6th grade math and it is due October 16 please I really need help we are doing simplifying expressions a
mel-nik [20]
Hey I'm in 6th too, Simplify means to solve the prob
8 0
4 years ago
Henri has $24000 invested in stocks and bonds. The amount in stocks is $6000 more than three times the amount in bonds. Call the
andrey2020 [161]

Answer:

Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

Step-by-step explanation:

Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:

6000 + 3B + B = 24000

3B + B = 24000 - 6000

4B = 18000

B = 18000/4

B = 4500

S = 6000 + 3x4500

S = 6000 + 13500

S = 19500

Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

7 0
3 years ago
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