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Damm [24]
3 years ago
14

PLEASE HELP:) :( What is the area of this Polygon? Enter your answer in the box

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0
7 x 5 = 35

1/2(7) x 2
3.5 x 2
7

35 + 7 = 42 Units squared
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I'm quite confused on how to solve 4 to the -2nd power. Could someone help?
leonid [27]
It's 1 over 4 to the 2nd or 1 over 16
6 0
3 years ago
A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
2 years ago
A sphere has a volume of 288 Pi in^3. Find the surface area of the sphere
lorasvet [3.4K]

Answer:

Step-by-step explanation:

The formula for determining the volume of a sphere is expressed as

Volume = (4/3) × πr³

The volume of the given sphere is expressed as 288π inches³. It means that

(4/3) × πr³ = 288π

4r³/3 = 288

4r³ = 3 × 288 = 864

r³ = 864/4 = 216

Taking cube root of both sides, it becomes

r = 6

The formula for determining the surface area of a sphere is expressed as

Area = 4πr²

π = 3.14

Therefore,

Surface area = 4 × 3.14 × 6² = 452.16 inches²

7 0
2 years ago
Hello it's mathhhhhh
yaroslaw [1]

Answer:

36

Step-by-step explanation:

4*6=24

3*4=12

24+12=36

8 0
2 years ago
Read 2 more answers
Please help!<br><br> Find the zeros for y=2x(x+6)(x+-14)
garri49 [273]

Answer:

-6;14

Step-by-step explanation:

x+6=0

x-14=0

4 0
2 years ago
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