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natka813 [3]
2 years ago
5

Help please. Number 3 or 4!

Mathematics
1 answer:
KIM [24]2 years ago
3 0

Answer:

3

Step-by-step explanation:

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erastovalidia [21]
.4 is the answer m8

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3 years ago
1+1 = what is it the number<br>​
anzhelika [568]
The answer is 2 if this is right can i please have brainlyest
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20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
Exact = 50 Approximate = 45
Nikitich [7]

Answer:

Approximate of error = 11.11 % (Approx.)

Step-by-step explanation:

Given:

Exact value = 50

Approximate value = 45

Find:

Approximate of error

Computation:

Approximate of error = [(Exact value - Approximate value)/Approximate value]100

Approximate of error = [(50 - 45)/45]100

Approximate of error = [(5)/45]100

Approximate of error = [0.11111]100

Approximate of error = 11.11 % (Approx.)

3 0
2 years ago
Find the square roots.
ahrayia [7]

Step-by-step explanation:

I think the answer would be

=1/31 and 1/31

6 0
3 years ago
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