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4 years ago

(12x2)/2+1!!!!!!!!!!!!!!

Mathematics

1 answer:

jeka57 [31]4 years ago

5 0

Answer:

Step-by-step explanation:

(12*2)/2+1 > 24/2+1 > 12+1 > 13

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mamaluj [8]

Hm..I'm pretty sure the answer is 34

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3 years ago

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WARRIOR [948]

Answer:

Formula

Step-by-step explanation:

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3 years ago

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There is a triangular parking lot at the local mall. The second angle of the triangular parking lot is six more than twice as la

Travka [436]

Answer:

The measure of the three angles are;

The first angle is 62°

The second angle is 28°

The third angle is 90°

Step-by-step explanation:

The given information are;

The shape of the parking lot = Triangular

Let the angles of the triangle be given as follows

First angle = A

Second angle = B

Third angle = C

The given triangle interior angle dimensions are;

A = 6 + 2× B

C = A + B

However, we have;

A + B + C = 180° (Angle sum property for a triangle)

Therefore;

A + B + C = 180° gives;

C + C = 180° (Transitive property)

2·C = 180°

C = 180°/2 = 90°

C = 90°

However, C = A + B therefore;

90° = A + B and, A = 6 + 2 × B, we get;

A + B = 90° (Symmetric property)

6 + 2× B + B = 90° (Substitution property)

6 + 3·B = 90°

3·B = 90° - 6° = 84°

B = 84°/3 = 28°

B = 28°

From, A = 6 + 2 × B, we have;

A = 6 + 2 × 28° = 62°

A = 62°

First angle = A = 62°

Second angle = B = 28°

Third angle = C = 90°

The measure of the three angles are;

First angle is 62°

Second angle is 28°

Third angle is 90°.

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3 years ago

The Scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. Response times are normally distr

IgorC [24]

<h2><u>Answer with explanation</u>:</h2>

Let $\mu$ be the population mean.

As per given , we have

$H_0:\mu \leq4\\\\ H_a: \mu >4$

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given $\sigma=1$ , so we perform one-tailed z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

, where $\mu$ = Population mean

$\sigma$ = Population standard deviation

n= sample size

$\overline{x}$ = Sample mean

For n= 18 , $\overline{x}=4.50$ , $\sigma=1$ , $\mu =4$ , we have

$z=\dfrac{4.5-4}{\dfrac{1}{\sqrt{18}}}\approx2.12$

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

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3 years ago

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Alexandra [31]

Ummmm uh.....fid the perimiter and diamiter and multiply them...

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