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zepelin [54]
2 years ago
9

The length of a rectangle is twice its breadth. If its length is decreased half of the 10 cm and the breadth is increased by hal

f of the 10 cm cm, the area of the rectangle is increased by 5 sq cm, more than 70 sq cm. Find the length of the rectangle.
Also....any armies, stays and blinkss?
Mathematics
1 answer:
Leto [7]2 years ago
6 0

Since the length of this rectangle is twice its breadth, the length is equal to 40 cm.

<h3>How to calculate the area of a rectangle?</h3>

Mathematically, the area of a rectangle can be calculated by using this formula:

Area = Length × Width

Based on the information provided, we have:

  • Its length is decreased half of the 10 cm ⇒ (length - 5)
  • Its breadth is increased by half of the 10 cm ⇒ (breadth + 5)
  • Its area is increased by 75 cm ⇒ (area + 5)

Substituting the parameters into the formula, we have:

LB + 75 = (L - 5)(B + 5)

2B² + 75 = (2B - 5)(2B + 5)

2B² + 75 = 2B(B + 5) - 5(B + 5)

2B² + 75 = 2B² + 10B - 5B - 25

5B = 75 + 25

5B = 100

B = 100/20

B = 20 cm.

For the length, we have:

L = 2B

L = 2 × 20

L = 40 cm.

Read more on rectangle here: brainly.com/question/25292087

#SPJ1

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Answer:

Therefore the value of x = 10 units

Step-by-step explanation:

Let label the Triangles first,

Δ ABC a right triangle at ∠ A =90°

Δ ADB andΔ ADC a right triangle at ∠ D =90°

Such that

AD = x

BD = 50

CD = 2

∴ BC = BD + DC = 50 + 2 = 52

To Find:

x = ?

Solution:

In right triangle  By Pythagoras Theorem,

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

In right triangle Δ ADB andΔ ADC  By Pythagoras Theorem we will have,

AB² =  BD² + AD²

AB² = 50² + x²            ..................equation ( 1 )

and

AC² = DC² + AD²

AC² = 2² + x²             ...................equation ( 2 )

Now in right triangle Δ ABC,

BC² = AB² + AC²

Equating equation  (1 ) and ( 2 ) and the given value we get

52² = 50² + x² + 2² + x²

∴ 2x² = 2704 - 2504

∴ 2x² =200

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8 0
3 years ago
If a car goes around a turn too quickly, it can leave tracks that form an arc of a circle. By finding the radius of the circle,
liubo4ka [24]
Given:
Segment AC = 130 feet
Segment CD = 70 feet

I think that I'll be using the Pythagorean Theorem in finding the value of r. r will be the hypotenuse

Segment CE = (r - 70 feet)

r² = a² + b²
r² = 130² + (r-70)²
r² = 16,900 + (r-70)(r-70)
r² = 16,900 + r² - 70r - 70r + 4900
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140r = 21,800
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r = 155.71 feet

The radius of the circle is 155.71 feet.

8 0
3 years ago
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Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

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\mu = 15.0

Standard deviation,

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= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})

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