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3 years ago

Use estimation to solve 2, 697/9

Mathematics

1 answer:

kotegsom [21]3 years ago

5 0

300 is the best answer plse make me brainliest

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Graph a line with a slope of 1/4 that contains the point (6, 3).

Semenov [28]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

$y-y1=m(x-x1)$

we have

$(x_1,y_1)=(6,3)$

$m=\frac{1}{4}$

substitute

$y-3=\frac{1}{4}(x-6)$

The easiest way to graph a line is to calculate the intercepts

The x-intercept is the value of x when the value of y is equal to zero

For y=0

$0-3=\frac{1}{4}(x-6)$

$-12=(x-6)$

$x=-12+6=-6$

The x-intercept is the point (-6,0)

The y-intercept is the value of y when the value of x is equal to zero

For x=0

$y-3=\frac{1}{4}(0-6)$

$y-3=-\frac{3}{2}$

$y=-\frac{3}{2}+3$

$y=1.5$

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

8 0

2 years ago

Please help me with this (5th grade math)

Tanya [424]

Answer:

kenis

Step-by-step explanation:

3 0

3 years ago

Find the area of the triangle belowunits given are cm, cm^2, cm^3

zloy xaker [14]

Answer:

$A_T=150cm^2$

Explanation: We need to find the area of the triangle, We know that the area of any right triangle is:

$A_T=\frac{1}{2}(b\times h)$

Therefore in the information given we have the following:

$\begin{gathered} h=20\operatorname{cm} \\ b=15\operatorname{cm} \end{gathered}$

Therefore the Area of this triangle is as follows:

$\begin{gathered} A_T=\frac{1}{2}(b\times h) \\ \therefore\rightarrow \\ A_T=\frac{1}{2}(20cm\times15cm)=\frac{1}{2}(20\times15)cm^2 \\ A_T=\frac{1}{2}(300)cm^2=150cm^2 \\ \therefore\rightarrow \\ A_T=150cm^2 \end{gathered}$

Note! Units are centimeter-squared

4 0

1 year ago

Select the Expressions that are equivalent to -2(4-3x)+(5x-2) PLZ help do tommorrow

Alborosie

Answer is B.........

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3 years ago

Common Denominators 15. Explain how you can find a common denominator for and

VLD [36.1K]

You can find a common denominator using the two denominators multiples.

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3 years ago