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myrzilka [38]
4 years ago
8

What is the driving time for a 1700 miles trip if you Drive an average speed of 53 mph

Mathematics
1 answer:
slavikrds [6]4 years ago
3 0

Answer:

32.08h

Step-by-step explanation:

1700/53= 32.08h is the time

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As you move up a linear demand​ curve, the price elasticity of demand in absolute value A. decreases. B. increases. C. stays the
Andreyy89

Answer:

The answers to the questions are;

B. increases.  

C. ​inelastic; increase.

Step-by-step explanation:

The price elasticity of demand for a linear demand in absolute value curve becomes smaller and smaller as we move downwards of the curve.

When the price elasticity of demand is calculated along a linear demand curve. This is so as for each pair of points at which the price elasticity of demand is calculated, the quantity demanded and the price change are somewhat  similar, but as we move towards the top of the demand curve, the high prices and the low quantities shows the increase in demand elasticity.

Also in the inelastic region, as it can be shown by the areas of the rectangles formed by to adjacent price points, increase in price, increases the total revenue.

6 0
3 years ago
Find the slope and reduce.
saveliy_v [14]
The slope will be 4/7. Let me know if you want an explanation. 
Answer: 4/7

Hope this helped!
8 0
3 years ago
Read 2 more answers
Two dices are tossed. What is probability that you will see even numbers on both dices? Answer should be in reduced
zimovet [89]

Answer:

3/6

Step-by-step explanation:

Well 3 is half of 6 and if you were to turn that into a fraction it would either be 3/6 or 1/2.

8 0
3 years ago
Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√
TiliK225 [7]
Parameterize the part of the sphere by

\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)

with 0\le u\le2\pi and 0\le v\le\dfrac\pi4. Then

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv

So the area of S (the part of the sphere above the cone) is given by

\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi
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4 years ago
Solve for x using the diagram
liraira [26]
Its bh 5 time 7 = 35 is ur hight 
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3 years ago
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