Answer:
The dimensions of the rectangle = 60ft by 107ft
Where 60 ft = Width of the playing field
107ft = Length of the playing field
Step-by-step explanation:
A playing field is Rectangular is shape, hence,
The formula for Perimeter of a rectangle = 2(L + W)
P = 334 ft
L = 47 + W
W = W
Hence we input these values in the formula and we have:
334 = 2(47 + W + W)
334 = 2(47 + 2W)
334 = 94 + 4W
334 - 94 = 4W
240 = 4W
W = 240/4
W = 60
There fore, the width of this playing field = 60 ft
The length of this rectangle is calculated as:
47 + W
47 + 60
= 107 ft
The length of this playing field = 107ft
Therefore the dimensions of the rectangle = 60ft by 107ft
Answer:
E(29/4,3)
Step-by-step explanation:
Given that,
Segment CD has point E located on it such that CE:ED = 3:5
The coordinates of C and D are (5, -6) and (11,18) respectively.
We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :
So, the coordinates of E are (29/4,3).
The standard equation for circumference
CC= 2pi(D/2)
plug in variables
CC=2pi(5656/2)
so the equation would be
CC=(2)(pi)(2828)
A. P[TTTTH] = .55^4*.45 = .0412
<span>b. P[HHHT] = .45^4*.55 = .0226 </span>
<span>c. 1/.45 = 2.222 </span>
<span>d. 1/.55 = 1.818</span>
