Equation: C=dπ
C=6·3.14
C=18.84
answer^^^
Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Answer:
Let the integers are p and q.
In case both integers are positive or negative, you add the numbers up and apply their sign to the sum.
<u>Examples:</u>
- 10 + 88 = 98
- -20 + (-15) = -35
In case one of the integers is negative and one positive.
Use absolute value in this case.
Subtract the numbers and apply the sign of the number with the greater absolute value.
<u>Examples:</u>
- - 10 + 15 = |15 - 10| = |5| = 5
- - 15 + 10 = - |15 - 10| = - |5| = -5
I attached the answer below. Please take a look. You're welcome.
Answer:
That’s ez pz
Step-by-step explanation:
