Explain how you can use absolute value to tell whether

Mathematics

1 answer:

kicyunya [14]3 years ago

3 0

Answer:

Let the integers are p and q.

In case both integers are positive or negative, you add the numbers up and apply their sign to the sum.

<u>Examples:</u>

10 + 88 = 98
-20 + (-15) = -35

In case one of the integers is negative and one positive.

p < 0, q > 0

Use absolute value in this case.

Subtract the numbers and apply the sign of the number with the greater absolute value.

<u>Examples:</u>

- 10 + 15 = |15 - 10| = |5| = 5
- 15 + 10 = - |15 - 10| = - |5| = -5

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tankabanditka [31]

Answer:

a^2+b^2=c^2 look below

Step-by-step explanation:

Count the squares so

3^2+4^2=5^2

3*3=9

4*4=16

5*5=25

9+16=25 and it does check out

this should help if u need more explanation ill be more then happy to explain to you

7 0

3 years ago

The derivative of y with respect to x, when y = 3e^5x - 2 is:

Ede4ka [16]

Answer: 15e^5x

Step - by - step

y=3e^5x - 2

By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].

d/dx [ 3e^5x ] + d/dx [ -2 ]

Evalute d/dx [ 3e^5x ]

Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].

3 d/dx [ e^5x ] + d/dx [ -2 ]

Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.

To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]

Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.

3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]

Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]

Multiply 5 by 3
15e^5x + d/dx [-2]

Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x

5 0

1 year ago

Find all solutions in the interval [0, 2π).

jekas [21]

First you must know that for remarkable angles: cos (0) = 1, cos (π) = - 1, cos (π / 2) = 0, cos (3π / 2) = 0, cos (2π) = 1. Then, by simple substitution in the given formula, you can find the solutions of x. Which for the interval [0, 2π) are: x = π, x = pi divided by two and x = three pi divided by two.Attached solution.