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4 years ago

Michael made 9/12 of his free throws at practice. What is 9/12 in simplest form?

2 answers:

8 0

3/4 because for the top number you do 9 divided by 3 and then for the bottom number you do 12 divided by 3 and you get 3/4

riadik2000 [5.3K]4 years ago

4 0

It would be 0.75 as a decimal or 3/4

You might be interested in

Please help im really confused Which expression is equivalent to 4(7 + 8)?

Hatshy [7]

Answer:

With the answer choices:

A. 11 + 8

B. 11 + 12

C. 28 + 12

D. 28 + 32

The answer would be 28+32.

Step-by-step explanation:

Use the distributive law.

4 * 7 = 28

4 * 8 = 32

Hope this helps!

8 0

3 years ago

21 is 30% of what number?

WARRIOR [948]

Answer:

21 is 30% of 70

Explanation:

We know that 100% is the original number.

Equation:

(21/30)*100

21/3 * 10

7 * 10

70 ....this is the answer, original number.

5 0

3 years ago

Read 2 more answers

What fraction is equivalent to 3/10 and has a denominator of 100

rosijanka [135]

Answer:

30/100

Step-by-step explanation:

This should be relatively easy since if the denominator is 100 then x/100 has to = 3/10

Since the denominator 10 has to be 100, you multiply by 10.

3 x 10 = 30

7 0

3 years ago

Read 2 more answers

45% of the students in Primary 5 are boys. There are 165 girls. How many more girls than boys are there in primary 5?

bezimeni [28]

Answer:

30 more

Step-by-step explanation:

hope it helps friend.

5 0

2 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago