3 years ago

PLEASE HELP ASAP!! WILL MARK BRAINLIEST!!

Mathematics

1 answer:

kipiarov [429]3 years ago

7 0

It’s B. Dan is 124 miles from home at noon and is traveling at 62 miles per hour

You might be interested in

I am a 2 digit number addy digits together and you get 5 I am not an odd number I am greater than 45 What am I?

melomori [17]

50
5+0=5
<45
Even not odd

7 0

3 years ago

Read 2 more answers

I need help with this... please log(x+3)64=3

nikdorinn [45]

Answer:

you got this

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Solve for x:<br><br> 2^x=17^x<br><br>

beks73 [17]

Answer:

x = 0

Step-by-step explanation:

Equation: 2ˣ = 17ˣ

For all equations like this, we will always end up with x = (a)x, a being some random number.

In that situation, that becomes (1 - a)x = 0 --> x = ⁰/₍₁ ₋ ₐ₎ --> x = 0

4 0

3 years ago

State if a triangle is acute, obtuse, or right.

Elza [17]

Answer:

acute

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Pls help me solve this

sammy [17]

Answer:

4 kg of sugar would contain $1.2 \times 10^9$ crystals.

Step-by-step explanation:

Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.

Thus, set up a proportion as follows:

3 kg : 9 × 10⁸ = 4 kg : x

$\frac{3}{9 \times 10^8} = \frac{4}{x}$

Solve for x. Cross multiply.

$3 \times x = 9 \times 10^8 \times 4$

$3x = 36 \times 10^8$

$3x = 3.6 \times 10^9$

Divide both sides by 3

$\frac{3x}{3} = \frac{3.6 \times 10^9}{3}$

$x = 1.2 \times 10^9$

4 kg of sugar would contain $1.2 \times 10^9$ crystals.

5 0

3 years ago